Answer:
131.39863 m/s
683205.94 Joules
Explanation:
m = Mass of person = 80 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height of the drop = 880 m
v = Speed
= Maximum speed = 140 km/h
Here the Potential and Kinetic energies are conserved
The velocity of Fritz Strobl is 131.39863 m/s
Taking friction into consideration
The work done by friction is 683205.94 Joules
Let <em>F₁ </em>and <em>F₂</em> denote the two forces, and <em>R</em> the resultant force.
<em>F₁ </em>and <em>F₂</em> point perpendicularly to one another, so their dot product is
<em>F₁ </em>• <em>F₂</em> = 0
<em />
We're given that one of these vectors, say <em>F₁</em>, makes an angle with <em>R</em> of 30°, so that
<em>F₁</em> • <em>R</em> = ||<em>F₁</em>|| ||<em>R</em>|| cos(30°)
But we also have
<em>F₁</em> • <em>R</em> = <em>F₁ </em>• (<em>F₁ </em>+ <em>F₂</em>) = (<em>F₁ </em>• <em>F₁</em>) + (<em>F₁ </em>• <em>F₂</em>) = <em>F₁ </em>• <em>F₁ </em>=<em> </em>||<em>F₁</em>||²
So, knowing that ||<em>R</em>|| = 100 N, we get that
(100 N) ||<em>F₁</em>|| cos(30°) = ||<em>F₁</em>||²
(100 N) cos(30°) = ||<em>F₁</em>||
||<em>F₁</em>|| ≈ 86.6 N
(And the same would be true for <em>F₂</em>.)
The formula for finding potential energy is: f= m*g*h. where "m" is mass of the object in question. "g" is the gravitational acceleration."h" is height above the ground. So, if we put in the values:
joules
Answer:
Explanation:
ω = 2π/ T = 2π/ 3.01 = 2.087 rad/s
x(t) = 0.290sin2.087t
v(t) = 0.290(2.087)cos2.087t
a(t) = -0.290(2.087²)sin2.087t
With these three equations, you should be able to plug in what you know to find other values