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katovenus [111]
3 years ago
8

The "Hangtime" or time spent in the air by a projectile is dependent on

Physics
1 answer:
jekas [21]3 years ago
8 0

Answer:

Density.

Explanation:

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_____ is the frictional force needed to slow an object in motion
s2008m [1.1K]

Answer:

<u>Drag force</u> is the frictional force needed to slow an object in motion

Explanation:

8 0
3 years ago
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What is the name and symbol of the element in the second row and fourteenth column of the periodic table? Hint: Review your peri
Papessa [141]
The answer is Carbon. Beyond being the only element listed here that is located in the second row, it is also in the fourteenth column of the table if you count from left to right. Hope this helps!
4 0
4 years ago
2. Which of the following wavelength properties would require a stopwatch to measure?
katovenus [111]

Answer:

<u><em>A. wavelength</em></u>

Explanation:

The others are about sound and how high it is. That has nothing to do with time.

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3 years ago
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The first ionization energy of a hydrogen atom is 2.18 aj (attojoules). what is the frequency and wavelength, in nanometers, of
jasenka [17]

1) Frequency: 3.29\cdot 10^{15}Hz

the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

E=2.18 aJ=2.18\cdot 10^{-18} J

The energy of a photon is given by

E=hf

where h=6.63\cdot 10^{-34}Js is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz


2) Wavelength: 91.2 nm

The wavelength of the photon can be found from its frequency, by using the following relationship:

\lambda=\frac{c}{f}

where c=3\cdot 10^8 m/s is the speed of light and f is the frequency. Substituting the frequency, we find

\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm

5 0
3 years ago
How does a large star create the elements? at what element does the star stop making new elements?
Dahasolnce [82]
They are fused in the core of the star due to great pressures and temperatures.  They are made all the way through iron.  At that point the star dies.  If it is a really large star it will become a supernova when it dies, creating all of the elements beyond iron as well, but only in its death.  No star can create anything beyond iron in its life cycle
4 0
3 years ago
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