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katovenus [111]
3 years ago
8

The "Hangtime" or time spent in the air by a projectile is dependent on

Physics
1 answer:
jekas [21]3 years ago
8 0

Answer:

Density.

Explanation:

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How would an unexpected result to an experiment affect the original hypothesis?
Kipish [7]

Answer:

it would by them changing their hypothisis and retrying the test again

Explanation:

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3 years ago
If you could travel with speed of light (3.0e5 km/s) it would take only 2.5 minutes to reach venus. how far is venus from earth
motikmotik
D=S/T ,S=3.0e5km/s × 2.5min×60
D=4.5×e6km
7 0
3 years ago
Why are “input” and “output” good words to use when discussing systems?
charle [14.2K]

Answer:

To determine how efficient that system is.

3 0
3 years ago
Read 2 more answers
Scientists need to know how to make measurements
Verizon [17]

Part of the scientific process involves sharing your results with other scientists. To do this, we all need to use the same measurement system, which you'll learn about in this lesson.

Imagine you're trying to find out how much an elephant weighs. You're pretty sure it weighs a lot, but you don't know the exact number. So you ask your teacher, and she tells you an elephant weighs the same as three hippos.

Well that's nice to know, but how much does a hippopotamus weigh? Again, you ask your teacher, and she tells you a hippopotamus weighs the same as five alligators. That's a cool fact to know, but you still don't understand how much an elephant weighs because comparing elephants to alligators can be confusing.

plz mark me as brainliest :)

4 0
3 years ago
Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st
pantera1 [17]

Answer:

d) v1 = v2 = v3

Explanation:

This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.

At the original point we have, for the three balls:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

At the final point we have, for the three balls:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

Since we have E_i=E_f, and E_i is the same for all balls, then E_f is the same for all balls, which means that v_f, the final velocity, is the same for all balls.

4 0
3 years ago
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