4 years ago

Given g(x) = -x + 4, solve for x when g(x) = 0.

Mathematics

1 answer:

Novay_Z [31]4 years ago

6 0

Answer:

Step-by-step explanation:

1) 0= -x+4

2) -4= - x

3) x= 4

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Find the vertices and foci of the hyperbola with equation (x-5)^2/81 -(y-1)^2/144 = 1

vesna_86 [32]

Given the equation of an hyperbola in the form:
$\frac{(x-a)^2}{b^2}- \frac{(y-c)^2}{d^2}=1$
Then the focus of the hyperbola is $(\pm\sqrt {b^2+d^2},0)$
Compute like this:
$\sqrt{81+144}=15$
So the two focus points are $(\pm15,0)$
The vertices are given by the formula: $(\pm a,0)$
We deduce the two vertices of the given hyperbola: $(\pm9,0)$
since $\sqrt{81}=9$