Question

1. Identify the vertex and the y-intercept of the graph of the function y=-2(x+ 2)+2.

Answer 1

Answer:

Please let me know if your quadratic is $y=-2(x+2)^2+2$.

And if so your vertex is (-2,2) and your y-intercept is (0,-6)

Step-by-step explanation:

It says vertex so I'm thinking you meant $y=-2(x+2)^2+2$.  Please correct me if I'm wrong.

The vertex form of a quadratic is $y=a(x-h)^2+k$.  It is called that because it tells you the vertex (h,k).

So if you compare the two forms you should see -h=2 while k=2.

-h=2 implies h=-2.

So the vertex is (h,k)=(-2,2).

To find the y-intercept, set x=0 and find y.

$y=-2(0+2)^2+2$

$y=-2(2)^2+2$

$y=-2(4)+2$

$y=-8+2$

$y=-6$

So the y-intercept is (0,-6).