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vlabodo [156]
3 years ago
14

What is the value of 5 in the number 583.2

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:500.0

Step-by-step explanation:

Hundred.Since the 5 isn’t a decimal meaning it doesn’t have the “th” at the end of the word and the 5 is clearly on the hundred.

How this helps :)

I would appreciate it if you gave me brainliest:)

Tell me if its wrong.

lfu29

Vera_Pavlovna [14]3 years ago
8 0
The voice alue equals 612.36
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jeka94

Answer:

V: LWH divided by 3

Step-by-step explanation:

V: lwh

V: 5(6)(9) ÷ 3 = 90

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How much does Taryn charge to mow a lawn?
Liula [17]

Answer:

Taryn charges $12.50 per lawn.

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3(n+4)=21 what does n =?
Brilliant_brown [7]

Answer:

3.

Step-by-step explanation:

3(n + 4) = 21

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3 years ago
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The expression below is the factorization of what trinomial-1(x+5)(x+6)
Nadya [2.5K]

Answer:

-x^2 - 11x -30

Step-by-step explanation:

Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.

ie: x(x) and x(6)

ie: x^2 + 6x

Then do the 5 times the things in the second parenthesis.

ie: 5(x) and 5(6)

ie: 5x + 30

Then add what you got from multiplying the first value to what you got from multiplying the second.

ie: x^2 + 11x + 30

This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.

ie: -x^2 - 11x -30

4 0
2 years ago
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