Price of one citron = 5 units
Price of one fragrant = 5/7 units = 0.71 units
Further explanation:
Let x be the price of one citron and
y be the price of one fragrant
Then according to given statement
10x+7y = 55 Eqn 1
7x+10y = 64 Eqn 2
Multiplying equation 1 by 7

This will be equation 3.
Multiplying equation 2 by 10

This will be equation 4.
Subtracting equation 3 from equation 4

So,
Price of one citron = 5 units
Price of one fragrant = 5/7 units = 0.71 units
Keywords: Linear Equations, Solving system of linear equations
Learn more about linear equations at:
#LearnwithBrainly
Answer: 92.84
Step-by-step explanation:
32 + 1.8° Celsius = 92.84° Fahrenheit
Answer:

Step-by-step explanation:

Answer:
a) increase by 4%
b) $ 98.54
Step-by-step explanation:
The given function is

We can rewrite this function as

Therefore the cost of the chemical increase over time by 4%
b) We want to find how much an ounce of the chemical cost in 2018.
Since 2010 to 2018, 8 years have passed.
We substitute x=8 to get:

