Diverging lens=concave lens
The image would be after the first focal point but before the lens and it will be smaller than the object. Look at my picture for reference. Please let me know if this helped you!
Answer:

Explanation:
It is given that,


Taking the cross product of v and v such that,




|w| = 13.92
Let
is the unit vector normal to the plane containing u and v. So,


Hence, this is the required solution.
Density = mass / volume = 7/14 = 0.5!g/cm^3
Answer:
The carrier lengthen is 0.08436 m.
Explanation:
Given that,
Length = 370 m
Initial temperature = 2.0°C
Final temperature = 21°C
We need to calculate the change temperature
Using formula of change of temperature



We need to calculate the carrier lengthen
Using formula of length

Put the value into the formula


Hence, The carrier lengthen is 0.08436 m.
With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees
ELECTRIC FORCE (F)
F = 
Where K = 9 x
N
/
The distance between
and
can be calculated by using Pythagoras theorem.
d = 
d = 46.7 cm = 0.467 m
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 1)/
= 2.7 x
/0.218
= 1.24 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 4)/
= 1.08 x
/0.1089
= 9.92 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 2)/
= 5.4 x
/0.1089
= 4.96 x
N
Summation of forces on Y component will be
=
-
Sin 45
= 9.92 x
- 1.24 x
Sin 45
= 9.04 x
N
Summation of forces on X component will be
=
-
Cos 45
= 4.96 x
- 1.24 x
Sin 45
= 4.08 x
N
Net Force = 
Net force = 
Net force = 9.9 x
N
The direction will be
Tan ∅ =
/
Tan ∅ = 9.04 x
/ 4.08 x 
Tan ∅ = 2.216
∅ =
(2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816