for what we can get from our side then we will see if they are being made in a letter or something <em>which</em><em> </em><em>is</em><em> </em><em>leading</em><em> </em><em>enormous</em><em> </em><em>growth</em><em> </em><em>in</em><em> </em><em>cities</em><em> </em><em>with</em><em> </em><em>brick</em><em> </em><em>and</em><em> </em><em><u>its</u></em><em><u> </u></em><em><u>own</u></em><em><u> </u></em><em><u>way</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>market</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>its</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>life</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>us</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>stay</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em>
neutron star is formed when the core of a star, that was one ginormous, collapse on its own mass thus it loses it's volume exponentially (y=a^x) while the mass of the star decreases linearly (y=mx+c) thus the neutron star has mass of 10 to 29 sun in the radius of 10 km( for scale earth has 6731 km) thus it's density is super high!!!!!!!!!!!!!!!!!!!
hope it helps you! ;)
<span>None of the choices makes a correct statement. The third choice is close,
but misleading.
The pencil appears broken because light bends away from a straight line
when it crosses the boundary between air and water.</span>
Answer:
The capacitance of your capacitor is 5.476 x 10⁻⁵ μF
Explanation:
Given;
diameter of the aluminum pie plates = 16 cm = 0.16 m
separation distance, d = 3.25 mm = 0.00325 m
voltage across the parallel plates = 6 V

where;
C is the capacitance of your capacitor
ε is the permittivity of free space = 8.85 x 10⁻¹² (F/m)
d is separation distance
A is the area of the plate = ¹/₄ (πd²) = 0.25 (π x 0.16²) = 0.02011 m²

Therefore, the capacitance of your capacitor is 5.476 x 10⁻⁵ μF
Answer:a
Explanation:
Given
![[H^+]=5.3\times 10^{-4}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D5.3%5Ctimes%2010%5E%7B-4%7D%5C%20M)
and 
Also ![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
therefore 


Thus 

and ![pOH=-\log [OH^{-}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E%7B-%7D%5D)
![[OH]^{-1}=10^{-10.25}](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-1%7D%3D10%5E%7B-10.25%7D)
![[OH]^{-1}=1.88\times 10^{-11}\ M](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-1%7D%3D1.88%5Ctimes%2010%5E%7B-11%7D%5C%20M)
As the pH is less than 7 therefore solution is acidic