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melisa1 [442]
3 years ago
12

Which statements about braking a car are true? A)The greater the kinetic energy of a car, the longer it takes for the car to sto

p. B) The lower the kinetic energy of a car, the longer it takes for the car to stop. C)If the speed of a car doubles, the car’s kinetic energy and braking distance quadruple. D)If the speed of a car doubles, the car’s kinetic energy and braking distance remain the same.
Physics
2 answers:
lianna [129]3 years ago
4 0

Answer:

I believe the correct option is <em>C</em>.

Thank You

NikAS [45]3 years ago
3 0

Answer:

option c  

Explanation:

Kinetic energy is due to the speed of a body.

K.E = \frac{1}{2}mv^2

When speed is doubled, the kinetic energy  is quadruple.

From third equation of motion, braking distance is also proportional to square of speed. Thus, when speed is doubled, the braking distance is quadruple.

Thus, option c is correct.

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A cat has a mass of 4.6 kg. What is its weight on Earth's surface?
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weight = 4.6 x 9.81

weight = 45.126

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3 years ago
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How often is water added to the Earth system?
rosijanka [135]
<span>Water is never added to earth system. Water forever remains in the water cycle on earth, so it goes from the ground, to the air, to the rain, to the sea, and round and round continuously. This cycle means that there does not need to be new water added to the earth, because it recycles any water that already exists of its own accord.</span>
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When a planet orbits the Sun, the
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2 years ago
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Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357°
lord [1]

Answer:

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

Explanation:

Por definición de entropía (S), medida en joules por Kelvin, tenemos la siguiente expresión:

dS = \frac{\delta Q}{T} (1)

Donde:

Q - Ganancia de calor, en joules.

T - Temperatura del sistema, en Kelvin.

Ampliamos (1) por la definición de calor latente:

dS = \frac{L_{v}}{T}\cdot dm (1b)

Donde:

m - Masa del sistema, en kilogramos.

L_{v} - Calor latente de vaporización, en joules

Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:

\Delta S = \frac{\Delta m \cdot L_{v}}{T}

Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que m = 0.50\,kg,L_{v} = 2.7\times 10^{5}\,\frac{J}{kg} and T = 630.15\,K, entonces el cambio de entropía es:

\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}

\Delta S = 214.235 \,\frac{J}{K}

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

3 0
3 years ago
I need to Swap the convergent lens to a menisc Congergent one And make a graph like the attached photo
weeeeeb [17]

A convergent meniscus lens is a lens that is composed of two spherical surfaces, like the on shown next:

The imaginary line that runs through the middle of the lens is the "symmetry axis".

In this type of lenses incident parallel beams of light converge in one point, as follows:

And thus we get the diagram.

4 0
1 year ago
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