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melisa1 [442]
2 years ago
12

Which statements about braking a car are true? A)The greater the kinetic energy of a car, the longer it takes for the car to sto

p. B) The lower the kinetic energy of a car, the longer it takes for the car to stop. C)If the speed of a car doubles, the car’s kinetic energy and braking distance quadruple. D)If the speed of a car doubles, the car’s kinetic energy and braking distance remain the same.
Physics
2 answers:
lianna [129]2 years ago
4 0

Answer:

I believe the correct option is <em>C</em>.

Thank You

NikAS [45]2 years ago
3 0

Answer:

option c  

Explanation:

Kinetic energy is due to the speed of a body.

K.E = \frac{1}{2}mv^2

When speed is doubled, the kinetic energy  is quadruple.

From third equation of motion, braking distance is also proportional to square of speed. Thus, when speed is doubled, the braking distance is quadruple.

Thus, option c is correct.

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The wavelength of red helium-neon laser light in air is 632.8 nm.(a) What is its frequency?(b) What is its wavelength in glass t
inn [45]

(a) 4.74 \cdot 10^{14}Hz

The frequency of a wave is given by:

f=\frac{v}{\lambda}

where

v is the wave's speed

\lambda is the wavelength

For the red laser light in this problem, we have

v=c=3\cdot 10^8 m/s (speed of light)

\lambda=632.8 nm=632.8\cdot 10^{-9} m

Substituting,

f=\frac{3\cdot 10^8 m/s}{632.8 \cdot 10^{-9} m}=4.74 \cdot 10^{14}Hz

(b) 427.6 nm

The wavelength of the wave in the glass is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 = 632.8\cdot 10^{-9} m is the original wavelength of the wave in air

n = 1.48 is the refractive index of glass

Substituting into the formula,

\lambda=\frac{632.8\cdot 10^{-9}m}{1.48}=427.6\cdot 10^{-9}m=427.6 nm

(c) 2.02\cdot 10^8 m/s

The speed of the wave in the glass is given by

v=\frac{c}{n}

where

c = 3\cdot 10^8 m/s is the original speed of the wave in air

n = 1.48 is the refractive index of glass

Substituting into the formula,

v=\frac{3\cdot 10^8 m/s}{1.48}=2.02\cdot 10^8 m/s

5 0
3 years ago
Fighter jet starting from airbase A flies 300 km east , then 350 km at 30° west of north and then 150km north to arrive finally
Tems11 [23]
A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North. 
4 0
3 years ago
How can you use distance and displacement to describe an object's motion​
andrew11 [14]

Answer:

distance can describe the total distance moved and displacement shows how far something has moved from its starting position (in a straight line from point a to point b) the object doesn't have to move in a straight line, but that is how displacement is measured

8 0
3 years ago
A copper wire 20 m long and 4mm in diameter is attached to the Ceiling and a 400 N
Fiesta28 [93]

Answer:

A

Explanation:

5 0
2 years ago
Why was Thompson's Plum pudding model a significant departure from previous models?
PSYCHO15rus [73]

Answer:

Thomson's cathode-ray tube experiments led him to develop the plum-pudding model, which stated that each atom had positively charged particles spread throughout its negatively charged matter. Reword the statement so it is true. ... More alpha particles were deflected than he expected.

Explanation:

Well.. I hope it helps you..

Just correct me if I'm wrong..

5 0
3 years ago
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