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melisa1 [442]
3 years ago
12

Which statements about braking a car are true? A)The greater the kinetic energy of a car, the longer it takes for the car to sto

p. B) The lower the kinetic energy of a car, the longer it takes for the car to stop. C)If the speed of a car doubles, the car’s kinetic energy and braking distance quadruple. D)If the speed of a car doubles, the car’s kinetic energy and braking distance remain the same.
Physics
2 answers:
lianna [129]3 years ago
4 0

Answer:

I believe the correct option is <em>C</em>.

Thank You

NikAS [45]3 years ago
3 0

Answer:

option c  

Explanation:

Kinetic energy is due to the speed of a body.

K.E = \frac{1}{2}mv^2

When speed is doubled, the kinetic energy  is quadruple.

From third equation of motion, braking distance is also proportional to square of speed. Thus, when speed is doubled, the braking distance is quadruple.

Thus, option c is correct.

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You stand new the earth's equator. A positively charged particle that starts moving parallel to the surface of the earth in a st
Talja [164]

Answer:

c. from south to north

Explanation:

since we know that:

F = qv×B

where F is the force and in this case is pointed upward

where v is the velocity due east

the field must be due north by the right hand rule

Therefore,  near the equator the magnetic field lines of the earth are directed north from south

3 0
3 years ago
A flat screen is located 0.55 m away from a single slit. Light with a wavelength of 544 nm (in vacuum) shines through the slit a
kobusy [5.1K]

Answer:

Explanation:

The diffraction pattern is given as

Sinθ = mλ/ω

Where m=1,2,3,4....

Now, when m=1

Sinθ = λ/ω

Then,

ω = λ/Sinθ

The width of the central bright fringe is given as

y=2Ltanθ. From trigonometric

Then,

θ=arctan(y/2L)

Given that,

y=0.052m

L=0.55m

θ=arctan(0.052/2×0.55)

θ=arctan(0.0473)

θ=2.71°

Substituting this into

ω = λ/Sinθ

Since λ=544nm=544×10^-9m

Then,

ω = 544×10^-9/Si.2.71

ω = 1.15×10^-5m.

5 0
3 years ago
An alien spaceship traveling at 0.600 c toward the Earth launches a landing craft. The landing craft travels in the same directi
Thepotemich [5.8K]

The distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

To find the answer, we have to know about the Lorentz transformation.

<h3>What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens?</h3>

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the distance to the Earth at the moment of the landing craft's launch as measured by the aliens.

  • It is given that; the spaceship is 0.200 ly from the Earth when the landing craft is launched.
  • By Lorentz transformation equation, the value of the distance to the Earth at the moment of the landing craft's launch as measured by the aliens will be,

        L=L_0\sqrt{1-\frac{V^2}{c^2} } =0.2ly\sqrt{1-\frac{(0.6c)^2}{c^2} }=0.2ly\sqrt{1-0.36}=  0.16ly

Thus, we can conclude that, the distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

Learn more about the frame of reference here:

brainly.com/question/20897534

SPJ4

5 0
2 years ago
Why does it take 2 days longer for the Moon to go from New Moon to New Moon when viewed form the Earth than it takes for the the
Vesnalui [34]

The time between two new Moon phases or two full Moon phases is 29.5 days. ... The difference of 29.5 and 27.3 is that while the Moon is orbiting the Earth, the Earth is moving along in its orbit so it takes longer for the Moon to reach the same position relative to the Sun.

5 0
3 years ago
An Eider duck is flying Northeast at 25 m/s at an angle of 36.9 degrees to the ground (from the positive
otez555 [7]

Answer:

Horizontal = 19.99212 m/s     Vertical = 15.0151 m/s

Explanation:

Horizontal = Cos(36.9) x 25

Vertical = Sin(36.9) x 25

6 0
3 years ago
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