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3 years ago

What statement is equivalent to q to p

Mathematics

1 answer:

Ber [7]3 years ago

5 0

Answer:

what are the options?

Step-by-step explanation:

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Select all equations that are equivalent to 2x + 2 = 10

snow_tiger [21]

Answer:

6x + 6 = 30

2x = 8

plz give brainlyist

Step-by-step explanation:

6x + 2 = 10

to get the first term to be 6x you need to mulitply by 3 but if you did then the equation would be 6x + 6 = 30 so it is not equivlent

6x + 6 = 30

if you multiply both side by 3 you get 6x + 6 = 30

2x+8

if you subtract 2 from both sides you get 2x = 8

6x = 10

to get the first term to be 6x you need to mulitply by 3 but if you did then the equation would be 6x + 6 = 30 then if you subtract 6 from both sides you get 6x = 24 so it is not equivlent

3 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n

Ratling [72]

Answer:

$k = \dfrac{1}{21}$

b) 0.476

c) 0.667

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

$P(y) = ky$

a) Property of discrete probability distribution:

$\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}$

b) at most four forms are required

$P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476$

c) probability that between two and five forms (inclusive) are required

$P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667$

8 0

3 years ago

HELP ! I've been stuck on this for over 15 mins. :(

Delvig [45]

A1 = first term = 8

Plug in a1 = 8:
an = 8 + (n - 1)d

FInd d:
Given that a2 = 5
5 = 8 + (2-1)d
5 = 8 + d
d = -3

Plug in d = -3:
an = 8 -3(n - 1)

Answer: an = 8 -3(n - 1) ; n ≥ 1

6 0

3 years ago

What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?

Aleksandr-060686 [28]

Implicit differentiation
take the deritivive with respect to x

first
y+2=(1/2)(x^2)-2sin(y)
take deritivitive
dy/dx+0=1/2(2x)-2(cosy)dy/dx
dy/dx=x-2cosy(dy/dx)
add 2cosy(dy/dx) to both sides
dy/dx+2cosy(dy/dx) =x
undistribute dy/dx
dy/dx(1+2cos(y))=x
divide both sides by 1+2cos(y)
$\frac{dy}{dx}= \frac{x}{1+2cos(y)}$
at (2,0)
x=2
y=0

$\frac{dy}{dx}= \frac{2}{1+2cos(0)}$
$\frac{dy}{dx}= \frac{2}{1+2(1)}$
$\frac{dy}{dx}= \frac{2}{1+2}$
$\frac{dy}{dx}= \frac{2}{3}$
the slope is 2/3

6 0

3 years ago

Categories the graph as linear increasing, linear decreasing, exponential growth, or exponential decay

DIA [1.3K]

Answer:

Step-by-step explanation:

This graph is both linear and decreasing, as we move from left to right.

7 0

4 years ago