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DaniilM [7]
4 years ago
6

WHAT HAPPENS WHEN A TEASPOON OF TABLE SALT IS STIRRED INTO A GLASS OF WATER

Chemistry
2 answers:
Anastaziya [24]4 years ago
8 0

Answer:

C) The salt and water form a solution

Explanation:

I got it correct on Apex.

makkiz [27]4 years ago
3 0

A

they make salt water

in chemistry we called that aqueous solutions

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Answer:

to calculate the mass of limestone magnesium used.

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3 years ago
Which type of property can be observed only by changing a substance into a different substance? A. intensive property B. extensi
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The answer would be D because a chemical property is Burning is a chemical property and a chemical property is any of material's properties that becomes evident during or after a chemical reaction that is any quality that can be established only by changing a substance's chemical identity.

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3 0
3 years ago
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How does the structure of the stigma aid in pollination?
inysia [295]
If the stigma is messed up it is hard for bees or insects to pollinate because the way they pollinate is by eating the nectar from the stigma and stick the pollen on their body and stick it on the stigma.

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4 0
4 years ago
The depletion of ozone (O3) in the stratosphere has been a matter of great concern among scientists in recent years. It is belie
Deffense [45]

<u>Answer:</u> Nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

<u>Explanation:</u>

To calculate the number of moles, we use the equation

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ....(1)

  • <u>For ozone:</u>

Given mass of ozone = 0.827 g

Molar mass of ozone = 48 g/mol

Putting values in above equation, we get:

\text{Moles of ozone}=\frac{0.827g}{48g/mol}=0.0172mol

  • <u>For nitric oxide:</u>

Given mass of nitric oxide = 0.635 g

Molar mass of nitric oxide = 30.01 g/mol

Putting values in above equation, we get:

\text{Moles of nitric oxide}=\frac{0.635g}{30.01g/mol}=0.0211mol

For the given chemical equation:

O_3+NO\rightarrow O_2+NO_2

By Stoichiometry of the reaction:

1 mole of ozone reacts with 1 mole of nitric oxide.

So, 0.0172 moles of ozone will react with = \frac{1}{1}\times 0.0172=0.0172moles of nitric oxide

As, given amount of nitric oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ozone is considered as a limiting reagent because it limits the formation of product.

  • Amount of excess reagent (nitric oxide) left = 0.0211 - 0.0172 = 0.0039 moles

By Stoichiometry of the reaction:

1 mole of ozone produces 1 mole of nitrogen dioxide.

So, 0.0172 moles of ozone will react with = \frac{1}{1}\times 0.0172=0.0172moles of nitrogen dioxide

Now, calculating the mass of nitrogen dioxide from equation 1, we get:

Molar mass of nitrogen dioxide = 46 g/mol

Moles of nitrogen dioxide = 0.0172 moles

Putting values in equation 1, we get:

0.0172mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.7912g

Hence, nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

8 0
4 years ago
How does an enzyme’s active site relate to its substrate?
Fofino [41]

Answer:

The enzyme's active site must be the mold shape of the substrate.

Explanation:

An enzyme and a substrate bind together in order to work. If the shapes of the 2 are different, they will not be able to bond together. If the shapes of the 2 fit glove-in-hand, then they will be able to bond together.

7 0
3 years ago
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