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Dominik [7]
3 years ago
5

Convert 75 seconds to hours​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0
It is 0.02083333 hours.
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A = 100(1+r)^4<br> Expand the right of this formula.<br> appreciate your help with an explanation
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Answer:

100r^4 + 400r^3 + 600r^2 + 400r + 100

Step-by-step explanation:

Expanding ( r + 1 )^4 gives :-

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So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-

100r^4 + 400r^3 + 600r^2 + 400r + 100

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3 years ago
Radical expressions Help pls multiple choice
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Answer:

4th option (sqrt(10))/2

Step-by-step explanation:

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8 0
3 years ago
the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr
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\bf \qquad \qquad \textit{direct proportional variation}\\\\&#10;\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{array}{llll}&#10;\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\&#10;\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}&#10;\end{array}

\bf f=k\sqrt{t}\quad \textit{we also know that }&#10;\begin{cases}&#10;f=300\\&#10;t=8&#10;\end{cases}\implies 300=k\sqrt{8}&#10;\\\\\\&#10;\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k&#10;\\\\\\&#10;\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\&#10;-------------------------------\\\\&#10;\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
5 0
3 years ago
Read 2 more answers
(20 POINTS AND BRAINLIEST ANSWER!!!)
alisha [4.7K]

PICTURE1:  They are both 45

PICTURE2: 810

8 0
3 years ago
What is the measure of X! Please help if you know how to do this!
deff fn [24]

Answer:

28°

Step-by-step explanation:

You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.

4 0
3 years ago
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