Answer:
7
Step-by-step explanation:
Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors
"
Find all the squared values that lies between 360 and 630
360< 19², 20², 21², 22², 23², 24², 25² < 630
19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.
Answer:
Use photomath
Step-by-step explanation:
sorry it doesnt answer your question but just use it it's free and great
Answer:
0.5
Step-by-step explanation:
Answer:
- The solution is (x, y) = (-2, 0)
- A graph is attached
Step-by-step explanation:
The graph shows the solution. The first equation has a y-intercept of -4 and a slope of -2, so will go through the point (-2, 0).
The second equation has a y-intercept of +4 and a slope of 2, so will go through the point (-2, 0).
Both equations have the same x-intercept, so that x-intercept is the solution to the system of equations.
Answer:
36 centimeters.
Step-by-step explanation:
1. To solve this problem you must find the Greatest common factor.
2. List the prime factor of 108 and 72:

3. Now, you must choose the common prime numbers with the lowest exponents and multiply them:
