Ask question

Ask question

All categories

3 years ago

5

Solve the system for X: y=3x +4 у=х+8 x +10

1 answer:

Anastasy [175]3 years ago

3 0

Answer: The answers are x=y/3–4/3, and x=y/9–10/9.

Step-by-step explanation: You’ll need to isolate the variable by dividing each side by factors that don't contain the variable.

You might be interested in

What is the rate of change of the function?<br>

vaieri [72.5K]

<h3>Answer is -2</h3>

I hope it is helpful for you ....

6 0

3 years ago

PLEASE HELP ME WITH THIS THANKS

Lady bird [3.3K]

What is M when R = 200? *

Step-by-step explanation:

6 0

3 years ago

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0

3 years ago

Cuánto es la mitad de cinco octavos

shutvik [7]

Mitad de $\frac{5}{8}'s$
Multiplicar $\frac{5}{8}$ por $\frac{1}{2}$
$(\frac{5}{8}) (\frac{1}{2}) = \frac{(5)(1)}{(8)(2)} = \frac{5}{16}$

4 0

3 years ago

Help with #20 please!!!!!

shepuryov [24]

Remember that things like this, always need to add up to 180°.

7 0

3 years ago