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3 years ago

A. illustrate that the system is in a safe state by demonstrating an order in which the processes may complete.

Business

2 answers:

Rashid [163]3 years ago

8 0

Question:

The question is incomplete. The snapshot of a system was not added. See below the remaining part of the question and the answers.

Allocation Max Available Available

ABCD ABCD ABCD

PO 2001 4212 3321

P1 31 21 5252

P2 2103 2316

P3 1312 1424

P4 1432 3665

Answer:

(a) safe sequence is P0 , P3, P4, P1, P2

(b) The request can be granted

Explanation:

Need Matrix

Need [i, j] = Max [i, j] – Allocation [i, j]

A B C D

P0 2 2 1 1

P1 2 1 3 1

P2 0 2 1 3

P3 0 1 1 2

P4 2 2 3 3

Available = (3 3 2 1)

1. Need(P0) < Available so, P0 can take all resources

Available = (3 3 2 1) + (2 0 0 1) (Allocation of P0) = (5 3 2 2)

2. Need(P3)<Available so, P3 will go next

Available = (5 3 2 2) + (1 3 1 2) = (6 6 3 4)

Like wise next P4, P1, P2 will get resources.

So safe sequence is P0 , P3, P4, P1, P2

Request from P1 is (1 1 0 0) and Available is (3 3 2 1)

As request(P1) < Available, we can grant request

Request from P4 is (0 0 2 0) and Available is (3 3 2 1)

As request(P4) < Available, we can grant request

Nuetrik [128]3 years ago

6 0

Answer:

Answer: (b) As request(P1) < Available, we can grant request

Explanation:

Need Matrix

Need [i, j] = Max [i, j] – Allocation [i, j]

A B C D

P0 2 2 1 1

P1 2 1 3 1

P2 0 2 1 3

P3 0 1 1 2

P4 2 2 3 3

Available = (3 3 2 1)

1. Need(P0) < Available so, P0 can take all resources

Available = (3 3 2 1) + (2 0 0 1) (Allocation of P0) = (5 3 2 2)

2. Need(P3)<Available so, P3 will go next

Available = (5 3 2 2) + (1 3 1 2) = (6 6 3 4)

Like wise next P4, P1, P2 will get resources.

So safe sequence is P0 , P3, P4, P1, P2

Request from P1 is (1 1 0 0) and Available is (3 3 2 1)

As request(P1) < Available, we can grant request

Request from P4 is (0 0 2 0) and Available is (3 3 2 1)

As request (P4) < Available, we can grant request

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