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Rudiy27
3 years ago
6

Find the distance between the two points. Enter the number that goes beneath the radical symbol. (PICTURE ABOVE]​

Mathematics
1 answer:
Alika [10]3 years ago
6 0

For this case we have that by definition, the distance between two points is given by:

d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}

We have the following points:

(x_ {1}, y_ {1}) :( 1,4)\\(x_ {2}, y_ {2}): (- 2, -3)

Substituting we have:

d = \sqrt {(- 2-1) ^ 2 + (- 3-4) ^ 2}\\d = \sqrt {(- 3) ^ 2 + (- 7) ^ 2}\\d = \sqrt {9 + 49}\\d = \sqrt {58}

Thus, the distance between the points is\sqrt {58}

ANswer:

d = \sqrt {58}

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How can I solve this problem?
HACTEHA [7]

Answer:

25*pi or

78.5 square units.

Step-by-step explanation:

If there was no shaded area, the area of the circle would be pi * r^2

r = 10

Area = pi * 10^2

Area = 100 * pi

Since there is a shaded area, the shaded part looks to be 1/4 of the whole. There's no indication of what it actually is, but 1/4 should be close enough.

Area_shade = 1/4 (100*pi)

Area_shade = 25 * pi

That's one answer.

Another is 25 * 3.14 = 78.5 square units

7 0
3 years ago
What is the equation of the quadratic graph with a focus of (1 ,3) and a directrix of y=1?
zimovet [89]
Check the picture below.

now, we know the directrix is at y = 1, and the focus point is at 1,3, well, notice the picture, the distance between those fellows is just 2 units.

the vertex is half-way between those fellows, therefore, the vertex will be at 1,2.

the distance "p", from the vertex to either the directrix or focus, is really just 1 unit.  Since the focus point is above the directrix, is a vertical parabola, and it opens upwards, like in the picture, and since it opens up, the "p" value is positive, or +1.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
4p(x- h)=(y- k)^2
\\\\
\boxed{4p(y- k)=(x- h)^2}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ( h, k)\\\\
 p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=1\\
k=2\\
p=1
\end{cases}\implies 4(1)(y-2)=(x-1)^2\implies 4(y-2)=(x-1)^2
\\\\\\
y-2=\cfrac{1}{4}(x-1)^2\implies y=\cfrac{1}{4}(x-1)^2+2

4 0
3 years ago
Please help this is urgent and I am being timed
Shkiper50 [21]
Hi there!

Pauline simplified the expression correctly.

Pauline made sure she used the distributive property and combined like terms after doing so.

Hope this helps !
5 0
3 years ago
I need help please?!):
motikmotik

Answer:

Option C:   $ \sqrt{\textbf{121}} $

Step-by-step explanation:

Given the side length of a square is 11 units.

Note that $ \sqrt{121} = \pm 11 $

Since, length cannot be negative, we can eliminate - 11.

Hence, the length of the side of the square is 11 units = $ \sqrt{11^2} = \sqrt{121} $.

Hence, the answer.

7 0
3 years ago
Elaine spent 7/10 of her paycheck, and 5/9 of the money she spent was spent on groceries. What part of her paycheck was spent on
Black_prince [1.1K]
The answer has to be 1,350 is that one of your options

6 0
3 years ago
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