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3 years ago

How many midsegments does a triangle have?

Mathematics

2 answers:

katrin2010 [14]3 years ago

8 0

A triangle has three possible midsegments<span>, depending on which pair of sides is initially joined.</span>

GREYUIT [131]3 years ago

4 0

The midsegments the triangle have is three

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If a Touchdown is worth 7 points and a

tigry1 [53]

Answer:

43 points

Step-by-step explanation:

a football field is 12 feet, so 12x3=36 and 36+7=43. So if maybe it would be 43? Lemme know if it's right <3. Hope this helped.

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3 years ago

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Sumi rides at a constant speed of 10 ft/s. Write an equation that expresses the distance d that sumi has traveled as a function

Shtirlitz [24]

Answer:

d = 10s

Step-by-step explanation:

The formula for calculating the speed of Sumi is expressed as;

Speed = distance/time

Given

Speed = 10ft/s

time = s seconds

Required

Distance travelled as a function of time;

from the formula;

Distance = Speed * time

Distance = 10 * s

d = 10s

Hence the equation that expresses the distance d that sumi has traveled as a function of the time s in seconds since she started riding her bike is;

d = 10s

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3 years ago

Charlie is trying to cover the shape shown with paper. He will NOT be covering the top and the bottom. How much paper will he ne

DENIUS [597]

You need to determine how much paper you need to cover the lateral side of the cylinder shown in the picture. For this, you have to calculate the surface area of the cylinder, which you can do using the following formula:

$A=2\pi rh$

Where

A is the area

π is the number pi, for the calculations we usually use up to the first two decimal values of this number, 3.14

r is the radius

h is the height of the cylinder

The given cylinder has a height of h=15m and a diameter of d=6m

To calculate the lateral area you need to use the radius. The diameter is twice the radius, so to determine the radius of the cylinder you have to divide the diameter by 2

$\begin{gathered} r=\frac{d}{2} \\ r=\frac{6}{2} \\ r=3 \end{gathered}$

Now you can calculate the lateral area as follows:

$\begin{gathered} A=2\pi rh \\ A=2\cdot3.14\cdot3\cdot15 \\ A=282.6m^2 \end{gathered}$

Charlie will need 282.6 m² to cover the lateral side of the cylinder.

6 0

1 year ago

Eh so im confused on this question ill give brainliest.

stiv31 [10]

Answer:

the perimeter is 28 and the area is 49

Step-by-step explanation:

a square has equals sides and i counted seven on each side for the perimeter. you multiply seven by seven to find the area

6 0

3 years ago

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Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

4 years ago