Answer:
dz / dt = -50
Step-by-step explanation:
To solve the chain rule must apply, we have all the necessary values to make the calculation, as follows:
using the chain rule, we find:
dz / dt = (∂z / ∂x) * (∂x / ∂t) + (∂z / ∂y) * (∂y / ∂t)
Evaluating when t = 9, we have to:
fx (6, 4) * g '(9) + fy (6, 4) * h '(9)
We know that g '(9) = −6; h '(9) = 4; fx (6, 4) = 9; fy (6, 4) = 1
Replacing:
(9 * -6) + (1 * 4) = -50
Por lo tanto dz / dt = -50
Total perimeter is 522 ft. I will guess the gym is a big rectangle.
Therefore, Perimeter of a rectangle = 2L + 2W
P= 2L+ 2W
We know 80 ft wide. so now we plug and chug the equation we came up with
P=522 ft
P=2L+ 2(80)
522=2L+ 160
L= 181
hope that helps
Answer:
I don't know what inductive reasoning is but, the next two numbers in the pattern are -243 and +729
Step-by-step explanation:
each number is being multiplied by a factor of (-3).
Answer:
I'm not sure if you mean each person has a car for 2 weeks and travels 500 miles each but if so the rental cost is $2,940.
If it is just one car for all 3 people the rental cost is $980
Step-by-step explanation:
renatl cost = r
weeks = w
miles = m
the equation would be r = $240w + $1m
and if there are 3 people you mulitply the answer by 3
Answer:
The answer is "Option B".
Step-by-step explanation:
The difference between most time and also the least spending time on Internet surfing is 3 hours. Since we do not have charts for tables etc., only 3 can be used we need. A range is defined as the difference between the largest and the smallest amounts. The range between both the largest as well as the smallest is unique. In this reply, it tells us that the gap between most time and the fewer hours invested surfing the web is 3 hours.
- In option A, it is wrong since the range has nothing to do with formulas. (Of course, the dividend with a divisor results in a quotient). Only subtraction and not division may be achieved.
- In option C, when all surf for exactly one hour, it could take the largest time of 3 hours and 3 hours, the last time. Add it into the equation and the range of the data present would've been 0.
- In option D, It is erroneous even as the range is not the mean, and the mean seems to be the average. We search for both the range, not the mean.