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3 years ago

The graph below represents the water path of a fire hose.

Mathematics

2 answers:

Gala2k [10]3 years ago

7 0

The x intercept is 42 the coordinates is (42,0) shows how far away the water sprays before touching the ground

tekilochka [14]3 years ago

5 0

Step-by-step explanation:

The x intercept is 42.

The 42 tells us where the water coming from the hose is touching the ground.

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3 years ago

A restaurant offers a dinner special in which diners can choose anyone of three appetizers, anyone of four entries, anyone of fi

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3 years ago

Who started the problem correctly? The problem form is (-5) - (-1 3/4).

Veronika [31]

Answer:

Shane started the problem correctly

Step-by-step explanation:

We are given problem (-5) - (-1 3/4).

Mariah started the problem as (-5) + 1 - 3/4

Shane started the problem as (-5) + 1 + 3/4

We need to find who started the problem correctly.

The problem should be started by converting the mixed fraction into improper fraction i,e

$-5-(-1\frac{3}{4})\\=-5-(-1-\frac{3}{4} )\\=-5-(-\frac{7}{4})$

Now we will solve bracket by multiplying -1 with term inside the bracket i.e

$=-5+\frac{7}{4}$

$= \frac{-13}{4}$

Let's compare both the procedures now:

Mariah:

$(-5) + 1 - \frac{3}{4}$

$=(-5) - \frac{1}{4}$

$=\frac{-21}{4}$

Therefore, Mariah did not start the problem correctly.

Shane:

$(-5) + 1 + \frac{3}{4}$

$= -5 + \frac{7}{4}$

$= \frac{-13}{4}$

Therefore, Shane started the problem correctly.

6 0

3 years ago

The least common multiple of 9 and 42 through prime factorization?

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

9= 3*3

42=3*7*2

7 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$