The formula for an exponential equation is y = a * b^x with a and b being a fixed value.
"a" would also be the Y intercept, which is where the graph touches or crosses the Y axis. In the given graph, the curved line touches the Y axis at 100, so the value of a would be 100.
Now we need to find b.
The blue dot at Y 50 is lined up with x = 1, so we can use the point (1,50)
Using the X and Y values we can solve for b:
format: y = a * b^x we replace the letters with the numbers above:
50 = 100 * b^1
b^1 = b so now we have:
50 = 100 *b
Divide both sides by 100 to get b by itself:
b = 50/100, which reduces to 1/2, so b = 1/2
So the equation of the graph becomes y = 100(1/2)^x
You may need to write the 1/2 as 0.5, not sure how you need to enter it.
Answer:
35+7t
Step-by-step explanation:
7(5t) {If you expand it}
7×5+7×t
35+7t
Answer:
t ≥ -12
Step-by-step explanation:
Divide the inequality by the coefficient of t. Because that value is negative, the sign gets reversed.
(-4t)/(-4) ≥ (48)/(-4)
t ≥ -12
Check the picture below.
so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).
because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,
![\bf \begin{cases} h=2\\ k=-3\\ a=6\\ c=2\sqrt{10} \end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1 \\\\\\ \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1 \\\\\\ c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2 \\\\\\ 4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2 \\\\\\ \sqrt{4}=b\implies 2=b\\\\ -------------------------------\\\\ \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ah%3D2%5C%5C%0Ak%3D-3%5C%5C%0Aa%3D6%5C%5C%0Ac%3D2%5Csqrt%7B10%7D%0A%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7B%5By-%20%28-3%29%5D%5E2%7D%7B%206%5E2%7D-%5Ccfrac%7B%28x-%202%29%5E2%7D%7B%20b%5E2%7D%3D1%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B%28y%2B3%29%5E2%7D%7B%2036%7D-%5Ccfrac%7B%28x-%202%29%5E2%7D%7B%20b%5E2%7D%3D1%0A%5C%5C%5C%5C%5C%5C%0Ac%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%282%5Csqrt%7B10%7D%29%5E2%3D6%5E2%2Bb%5E2%5Cimplies%202%5E2%28%5Csqrt%7B10%7D%29%5E2%3D36%2Bb%5E2%0A%5C%5C%5C%5C%5C%5C%0A4%2810%29%3D36%2Bb%5E2%5Cimplies%2040%3D36%2Bb%5E2%5Cimplies%204%3Db%5E2%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%7B4%7D%3Db%5Cimplies%202%3Db%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B%28y%2B3%29%5E2%7D%7B%2036%7D-%5Ccfrac%7B%28x-%202%29%5E2%7D%7B%202%5E2%7D%3D1%5Cimplies%20%5Ccfrac%7B%28y%2B3%29%5E2%7D%7B%2036%7D-%5Ccfrac%7B%28x-%202%29%5E2%7D%7B%204%7D%3D1)
Answer:
Step-by-step explanation:
5. You are asked to write an equation of the line in slope-intercept form, so you need to determine the slope of the line and the y-intercept.
You're lucky. One of the points, (0,1), has an x-coordinate of 0, so you know that the y-intercept is 1.
Use the coordinates of the points to determine the slope of the line.
slope = (difference in y-coordinates)/(difference in x-coordinates) = (10-1)/(3-0) = 9/3 = 3
The slope-intercept equation of the line is y = 3x+1
:::::
7. When x = 0, function A = 0 and function B = 3, so function B has a greater initial value.
