The number of moles of gas in the container would be 4.62 moles
<h3>Ideal gas law</h3>
According to the ideal gas law:
PV = nRT, where P = pressure, V, volume, n = mole number, and R = constant = 8.31
In this case, V = 58.953 L, P 467.81 kPa, and T = 719.11 K
Making n the subject:
n = PV/RT = 58.953 x 467.81/8.31 x 719.11 = 4.62 moles
More on the ideal gas law can be found here:brainly.com/question/13821925
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The volume occupied by one mole of any gas at standard temperature(0o) and pressure(1 atm) is 22.4 litres. This volume is a close approximation and different gases vary slightly. The molar volume of any gas at S.T.P. is 22.4L .The mole of any gas can therefore be found using the expression on the right.
In the question, the number of atoms per unit cell is required for:
A) Polonium (Po)
In polonium, the structure is simple cubic, meaning there are 8 corner atoms, which add up to one atom per unit cell.
B) Manganese (Mn)
The structure of the Mn can be considered to be a body centered cubic (BCC) and the number of atoms for this is 8 corner atoms and 1 central atoms, making a total of 2 atoms per unit cell.
C) Silver (Ag)
Silver has a face centered cubic (FCC) unit cell structure, where there are 8 corner atoms and 6 atoms on the faces, so there are a total of 4 atoms per unit cell.
I am not 100% this is right but
Hope this helps :))