Answer:<span> a) the process for the first ionization energy
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<span>Every time you take a electron you're requiring more and more energy. Expelling the first one
will require less energy than expelling the second and the second will
require less than the third, and so on.
When you take the first one, the atom becomes positive and with that the negative forces of the electron will be more attracted to the positive
charge. The more electrons that are lost, the
more positive this ion will become, causing it to be more difficult to separate the
electrons from the atom.
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.A solution that serves as a pH indicator may be made using red cabbage, which is frequently available in homes. In essence, the color of the cabbage depends on the acidity of the solution and a pigment molecule called flavin or anthocyanin.
To determine whether a material is an acid or a base, red cabbage indicator is a purple-colored solution
Vinegar is an acid and its pH value is less than 7 and hence
Red color is produced
Baking soda is base and its pH value is greater than 7 and between 8-9
and the color produced is sky blue
Bleach is the green which is also a basic and because the pH value is 10-11
Householder cleaner is having pH 11-13 which is basic and hence the yellow is the color of household cleaner .
A basic solution goes away from being basic and toward the center of the pH scale when an acid is introduced. The base is "neutralized" in this manner.
Learn more about pH value here
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The number of protons in the nucleus of the atom, I believe. c:
Answer:
molarity of acid =0.0132 M
Explanation:
We are considering that the unknown acid is monoprotic. Let the acid is HA.
The reaction between NaOH and acid will be:
![NaOH+HA--->NaA+H_{2}O](https://tex.z-dn.net/?f=NaOH%2BHA---%3ENaA%2BH_%7B2%7DO)
Thus one mole of acid will react with one mole of base.
The moles of base reacted = molarity of NaOH X volume of NaOH
The volume of NaOH used = Final burette reading - Initial reading
Volume of NaOH used = 22.50-0.55= 21.95 mL
Moles of NaOH = 0.1517X21.95=3.33 mmole
The moles of acid reacted = 3.33 mmole
The molarity of acid will be = ![\frac{mmole}{volumne(mL)}=\frac{0.33}{25}=0.0132M](https://tex.z-dn.net/?f=%5Cfrac%7Bmmole%7D%7Bvolumne%28mL%29%7D%3D%5Cfrac%7B0.33%7D%7B25%7D%3D0.0132M)