First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:
2as = v² - u²
Because the final velocity v is 0 in such cases
s = -u²/2a; because both u and a are downwards, the negative sign cancels
s = 14.5² / 2*9.81
s = 10.72 meters
Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m
We will use the formula
s = ut + 0.5at²
to find the time taken with the initial velocity u = 0.
55.72 = 0.5 * 9.81 * t²
t = 3.37 seconds
Answer:
Explanation:
It is given that,
Mass of the car 1,
Initial speed of the car 1,
Mass of the car 2,
Initial speed of the car 2,
It is mentioned that train cars are coupled together by being bumped into one another. Let V is the final velocity of the train cars after the collision. It can be calculated using the conservation of linear momentum as :
So, the final speed of the coupled train cars is 0.129 m/s towards x axis. Hence, this is the required solution.
Answer:
A. Far away stars show a red shift and B. Microwave background creation is found all over the observational universe
Explanation:
Red shift in color indicates that galaxies are moving away from Earth. This is proof that the Universe is continously expanding, which also supports the big bang theory.
The Big Bang theory predicts that the early universe was a very hot place and that as it expands, the gas within it cools. Thus the universe should be filled with radiation that is literally the remnant heat left over from the Big Bang, called the “cosmic microwave background".
I hope this helps :)
Answer:
(a) increase by times
Explanation:
Natural frequency of a wave in a string is given by:
where, L is the length of the string, T is the tension in the string and is the linear density of the string.
Considering the length and linear density of the string are constant, if the tension in a string is doubled, the natural frequency of the string would:
Thus, the natural frequency of the string would increase by times.