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JulijaS [17]
3 years ago
13

A scooter has a mass of 250 kg. A constant force is exerted on it for 60.0 s. During the time the force is exerted, the scooter

increases its speed from 0.00 m/s to 28.0 m/s. What is the magnitude of the force exerted on the scooter?​
Physics
1 answer:
storchak [24]3 years ago
7 0

Answer:

5500

Explanation:

I cant explain it but when i asked my teacher thats what he told me

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Someone help me with this
lutik1710 [3]

Answer:

I can't read the questions they aren't in the photo

6 0
2 years ago
The barometer of a mountain hiker reads 930 mbars at the beginning of a hiking trip and 780 mbars at the end. Neglecting the eff
lara31 [8.8K]
We could use the change of pressure to calculate for the height climbed by the mountain hiker. The change of pressure is given by

p = rho * g * h, where p is the change of pressure, rho is the air density, g is the acceleration due to gravity, and h is the height.

Using the conversion 1 mbar = 100 Pa,

(930 - 780)(100) = (1.20)(9.80)h
15000 = 1.20*9.80*h

h = 1.28 km
6 0
4 years ago
The potential energy of an object attached to a spring is 2.60 J at a location where the kinetic energy is 1.40 J. If the amplit
anyanavicka [17]

Answer:

This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant. 

 U = (1/2)kx^2 

 U = (1/2)(5.3)(3.62-2.60)^2 

 U =  2.75706 J

Read more on Brainstorm - httpd://brainstorm/question/7981441#read more

Explanation:

6 0
3 years ago
What is the main idea of this text of "Phillis Wheatley"
Troyanec [42]

Answer:

The main idea of the text is to tell you how Phillis wheatley grew up and what the person life was like

7 0
3 years ago
An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster.
Dmitry [639]

Answer:

640 J

640 J

Explanation:

ΔKE = ½ mv² − ½ mu²

ΔKE = ½ m (v² − u²)

ΔKE = ½ (80 kg) ((5 m/s)² − (3 m/s)²)

ΔKE = 640 J

Work = ΔE

Work = 640 J

5 0
3 years ago
Read 2 more answers
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