How much more is 10,245 than 6,769

Mathematics

2 answers:

inysia [295]2 years ago

4 0

Answer:3,476

Step-by-step explanation: Just subtract them

Ludmilka [50]2 years ago

4 0

Answer:

3476

Step-by-step explanation:

You said Than and in math Than mean to subtract. The equation has become 10,245-6,796. When you subtract you get 3476.

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What is the gradient of the line (-4, 10) to (-2, 6)<br>

Andre45 [30]

Answer:

（2,-4）

Step-by-step explanation:

-4＋2＝-2

10＋-4＝10-4＝6

6 0

2 years ago

20 POINTS!!!

notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$