Domain of f(x)=3x+6,g(x)=x+1

1 answer:

7 0

Here you have shared two separate functions, f(x) and g(x). You have not indicated how f and g interact. Is g supposed to be the input to f? or what?

The domains of f and g are "the set of all real numbers."

If you meant "find the domain of f(g(x))," then we're finding the domain of
3(x+1)+6, which happens to be the same as before: "the set of all real numbers."

Kindly check to ensure that you have shared ALL of the given problem.

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No is divisible by 7 if n is divided by 2 3 4 5 the remainder is 1 what is the smallest value that n could b

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Answer: $301$

Step-by-step explanation:

Since, The LCM of numbers given numbers $2$ , $3$ , $4$ and $5$ is $60$ .

Thus, the number that gives 1 as reminder and is the multiple of 7 is $60 n + 1$

Where n is any positive integer,

Since, For $n = 5$ ,

The number is, $60\times 5 + 1 = 300 + 1 = 301$

Which is divisible by $7$ .

Thus, the required number is 301.

Note : For n = 1, 2 3 and 4, numbers are 61, 121, 181 and 241

But they are not the multiple of 7.

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