55. If it says 12 more, you add 12 to 43 to get 55.
The solution is 
<em><u>Solution:</u></em>
Let us assume,
<em><u>Given system of equations are:</u></em>
<em><u>Rewrite the equation using "a" and "b"</u></em>
2a - 3b = -5 ------------ eqn 1
4a + 6b = 14 -------------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 2</u></em>
2(2a - 3b = -5)
4a - 6b = -10 ------------- eqn 3
<em><u>Add eqn 2 and eqn 3</u></em>
4a + 6b = 14
4a - 6b = -10
( - ) --------------------
8a = 4
Substitute a = 1/2 in eqn 1
Now let us go back to our assumed values
Substitute a = 1/2 in assumed values
Substitute b = 2 in assumed value
Thus the solution is
The question is incomplete as the cost price isn't given. However, taking the cost price as x :
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
Let :
Cost price when new = x
Cost price when sold = 4/5 * cost price when new
Cost when sold = 4/5 of x = 4x/5
Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)
Hence,
Amount of money lost on the car = (x - 4x/5)
x - 4x/5 = (5x - 4x) / 5 = x / 5
To obtain the exact price, kindly input the omitted cost when new for x.
Answer:
it's d
Step-by-step explanation:
because the answer would be the same on both sides
13 is C, √10
Rational numbers are numbers that can be expressed as a ratio, or a fraction.
14 is C, 9.5 × 10^5
