Arrange the following molecules according to the strength of their dispersion forces. Organize in order from largest to smallest
1 answer:
Explanation:
The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.
Therefore, more is the surface area occupied by the carbon chain more will be the dispersion forces present in it. Hence, less is the surface area occupied by a molecule less will be the dispersion forces present in it.
Hence, the given molecules are organized from largest to smallest dispersion forces as follows.
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The mass percent lithium hydroxide in the mixture with potassium hydroxide, calculated from the equivalence point in the titration of HCl with the mixture, is 19.0%.
The mass percent of lithium hydroxide can be calculated with the following equation:
(1)
Where:
(2)
We need to find the mass of LiOH.
From the titration, we can find the number of moles of the mixture since the number of moles of the acid is equal to the number of moles of the bases at the equivalence point.
Since mol = m/M, where M: is the molar mass and m is the mass, we have:
(3)
Solving equation (2) for m_{KOH} and entering into equation (3), we can find the mass of LiOH:
Solving for , we have:
Hence, the percent lithium hydroxide is (eq 1):
Therefore, the mass percent lithium hydroxide in the mixture is 19.0%.
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Taking into account the reaction stoichiometry, the theorical yield for the reaction is 8.0467 grams of NH₃.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
3 H₂ + N₂ → 2 NH₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- H₂: 3 moles
- N₂: 1 mole
- NH₃: 2 moles
The molar mass of the compounds is:
- H₂: 2 g/mole
- N₂: 28 g/mole
- NH₃: 17 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- H₂: 3 moles ×2 g/mole= 6 grams
- N₂: 1 mole ×28 g/mole= 28 grams
- NH₃: 2 moles ×17 g/mole= 34 grams
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 28 grams of N₂ reacts with 6 grams of H₂, 10.4 grams of N₂ reacts with how much mass of H₂?
<u><em>mass of H₂= 2.2286 grams</em></u>
But 2.2286 grams of H₂ are not available, 1.42 grams are available. Since you have less mass than you need to react with 10.4 grams of N₂, H₂ will be the limiting reagent.
<h3>Definition of theorical yield</h3>The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Theoretical yield in this case</h3>Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 34 grams of NH₃, 1.42 grams of H₂ form how much mass of NH₃?
<u><em>mass of NH₃= 8.0467 grams</em></u>
Then, the theorical yield for the reaction is 8.0467 grams of NH₃.
Learn more about the reaction stoichiometry:
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