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Bad White [126]
3 years ago
9

What is charge of an nucleus of an atom?

Chemistry
2 answers:
Naily [24]3 years ago
6 0

Answer:

Positive

Explanation:

sweet [91]3 years ago
5 0
Positive................
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An aluminum plate is 78 cm wide and 35 cm long. The mass of the plate is 44,226 g. Determine its thickness. [The density of lead
Artemon [7]

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i try to solve it for you, and i aplode a similer question for you

Explanation:

6 0
3 years ago
Enter the formula for the polyatomic ion in MnCO3.
joja [24]
The formula is Mn2+CO2= MnCO3
8 0
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Ammonium (NH4+), carbonate (CO32−), and phosphate (PO43−) are all examples of: (a) multivalent metals (b) polyatomic ions (c) co
PtichkaEL [24]

Answer:

Option b) polyatomic ions

Explanation:

Polyatomic ions are ions consisting of two or more atoms.

From the question given above, we can see that each ions consist of more than one atom as shown below:

Ions >>>>>> Number of atom present

NH4+ >>>>> 2

CO32− >>>> 2

PO43− >>>> 2

Thus, we can say that the above ions are polyatomic ions.

5 0
3 years ago
Behind your house, there's a gorgeous pond filled with frogs. You notice that the frogs behind Mr. Archer's house often have thr
borishaifa [10]

Answer:

Group B is the control group

Explanation:

In an experiment, a control group is the standard to which comparisons are made in an experiment.

4 0
3 years ago
2NaClO3 ——> 2NaCl + 3O2
Alborosie

Answer:  

<h3>1) 208.09 g</h3><h3>2) 7.11 × 10²² particles</h3>

<h2>Explanation:</h2><h3>NUMBER ONE</h3>

<u>Find moles of Known Substance (NaCl)</u>

Moles of NaCl = mass ÷ molar mass

                        =  114.25 g ÷ 58.44 g/mol

                        = 1.955 mol

<u>Use Mole Ratio of Known to Unknown (NaCl : NaClO₃) to Determine Moles of Unknown</u>

The mole ratio of NaCl to NaClO₃ is 2 to 2 or simply 1 to 1.

This means that for each mole of NaCl produced the same number of moles of NaClO₃ was decomposed.

∴ since moles of NaCl = 1.955 mol,

then moles of NaClO₃ = 1.955 mol

<u>Find Mass of Unknown </u>

Mass of NaClO₃ = moles × molar mass

                           = 1.955 mol × 106.44 g/mol

                           =  208.09 g

<h3>NUMBER TWO</h3>

<u>Determine the Moles of Known (O₂)</u>

moles of O₂ = (volume × density) ÷ molar mass

                    = (68.30 L × 0.0828 g/L) ÷ 32 g/mol

                    = 0.177 mol

<u>Use Mole Ratio of Known to Unknown (O₂ : NaClO₃) to Determine Moles of Unknown</u>

Mole ratio of O₂ : NaClO₃ is 3 : 2. Therefore for each mole of oxygen produced, ²/₃ the moles of NaClO₃ is produced.

∴ if moles of O₂  =  0.177 mol

then moles of NaClO₃ =  0.177 mol × ²/₃

                                     = 0.118 mol

<u>Find the Number of Particles of Unknown</u>

Number of particles  = moles × Avogadro's Number

                                  = 0.118 mol × (6.022 × 10²³ particles/mol)

                                  =  7.11 × 10²² particles

3 0
3 years ago
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