Method:
1) Find the atomic number in a periodic table: the number of electrons equal the atomic number
2) Use Aufbau rule
Element atomic number electron configuration
<span>
P 15 1s2 2s2 2p6 3s2 3p3
Ca 20 </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2
</span>Si 14</span><span> 1s2 2s2 2p6 3s2 3p2
S 16</span><span><span> 1s2 2s2 2p6 3s2 3p4
</span>Ga 31. </span><span><span> 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p</span> </span>
Its d its the only one that makes sense
Answer:
ScCl₂
General Formulas and Concepts:
<u>Chemistry</u>
- Reading a Periodic Table
- Reaction Prediction
- Determining Chemical Compounds
Explanation:
<u>Step 1: Define</u>
Scandium (II)
Cl
<u>Step 2: Determine Charges</u>
Sc²⁺
Cl⁻
<u>Step 3: Predict Compound</u>
<em>We need to balance out the charges so the overall charge is 0.</em>
ScCl₂
<u>Step 4: Reaction</u>
RxN: Sc²⁺ + Cl₂ → ScCl₂
Answer:
- One mole of oxygen was used in this reaction.
- Two moles of water were produced from this reaction.
Explanation:
In addition: -<em> </em><em>T</em><em>w</em><em>o</em><em> </em><em>m</em><em>o</em><em>l</em><em>e</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em> </em><em>w</em><em>e</em><em>r</em><em>e</em><em> </em><em>u</em><em>s</em><em>e</em><em>d</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
Answer: The chemical formula for the formula given in the image is 
.
Explanation: There are many ways in which a model can be represented:
- Molecular Formula
- Ball and Stick formula
- Expanded Formula
- Condensed Formula
- Skeletal Formula
This molecule is represented by the Expanded Structural Formula and by seeing in the image we can count the number of each element present.
Number of Carbon atoms present = 4
Number of Hydrogen atom present = 9
Number of Oxygen atom present = 2
Correct representation for this will be .
