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Zepler [3.9K]
3 years ago
12

What happens when copper sulphate reacts with hydrogensulphide?​

Chemistry
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

When hydrogen sulphide gas is passed through a blue solution of copper sulphate, a black precipitate of copper sulphide is obtained and the sulphuric acid so formed remains in the solution. In this reaction, cupric ions (from copper sulphate) combine with sulphide ions (from hydrogen sulfide) to form cupric sulphide.

stiv31 [10]3 years ago
7 0

Answer:

When hydrogen sulphide gas is passed through a blue solution of copper sulphate, a black precipitate of copper sulphide is obtained and the sulphuric acid so formed remains in the solution. In this reaction, cupric ions (from copper sulphate) combine with sulphide ions (from hydrogen sulfide) to form cupric sulphide.

Explanation:

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Select all of the following statements that are false about ΔGo and ΔG:a) If the reaction has a large negative ΔGo value, the re
OLEGan [10]

Answer:

a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔGo and ΔG have the same magnitude, they just have opposite signs.

Explanation:

The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by \Delta G. It is observed that the values of \Delta G changes with experimental conditions such as temperature , pressure , concentration etc.

\Delta G^0 is the standard free energy change which is a balance of two natural tendencies of any system.

  1. Minimization of potential energy or enthalpic factor \Delta H^0

Maximization of disorderliness or entropic factor T\Delta S^0

Mathematically; \Delta G = \Delta H^0 - T\Delta S^0

Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:

ΔG⁰ and ΔG can have different values, they don't even have to have the same sign

For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point

If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.

while the false statements include:

a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.

7 0
3 years ago
Task Card #1
kumpel [21]

Answer:

B. Gas formation

Explanation:

When you combine baking soda and vinegar - which I'm assuming happened to create this reaction - it forms carbon dioxide, a gas.

5 0
3 years ago
How many atoms of iodine are needed to react with one atom of magnesium?
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Answer:

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Explanation:

4 0
3 years ago
A certain gas has a volume of 500.0 mL at 77.0°C and 600KPa. Calculate the temperature if the volume decreased to 400.0 mL and t
Jlenok [28]

Answer:

354.67K

Explanation:

Applying

P₁V₁/T₁ = P₂V₂/T₂................. Equation 1

Where Where P₁ = initial pressure, T₁ = Initial temperature, V₁ = Initial Volume, P₂ = Final pressure, V₂ = Final Volume, T₂ = Final Temperature.

From the question, we are ask to look for the final temperature,

Therefore we make T₂ the subject of the equation

T₂ = P₂V₂T₁/P₁V₁............. Equation 2

Given: P₁ = 600 kPa, V₁ = 500 mL, T₁ = 77 °C = (273+77) = 350 K, P₂ = 760 kPa, V₂ = 400.0 mL

Substitute these values into equation 2

T₂ = (760×400×350)/(600×500)

T₂ = 354.67 K

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An allergy pill has the following information on its label:
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The answer should be A
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