5/12+3/5= what's the answer

1 answer:

6 0

Make bottom numbre same
has to be 12 times 5 or 60

5/12 times 5/5=25/60
3/5 times 12/12=36/60

5/12+3/5=25/60+36/60=61/60=1 and 1/60

You might be interested in

The base of a cylindrical

KengaRu [80]

Answer:

Step-by-step explanation:

3 0

2 years ago

What is 3a squared add 7 a

vfiekz [6]

The answer is: " 9a² + 7a " .
_________________________________
Note: (3a)² + 7a = (3a)*(3a) + 7a = 9a² + 7a .
_________________________________

3 0

3 years ago

Please help me!!!!! <br>find the area of a square with a side length of 24.6 km

lubasha [3.4K]

It would be 24.6 ×24.6
it's 605.16

4 0

3 years ago

What is the answer to this question ?

STALIN [3.7K]

A is not commutative with the above expression
your answer is A

4 0

3 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago