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3 years ago

Number 10 please and fast answer

Chemistry

2 answers:

marshall27 [118]3 years ago

6 0

Answer: A. Atom

Explanation:

Atoms are the building blocks of all materials, no matter how simple or complicated the material is. An element is made up of only one type of atom. Compounds are made up of different types of atoms combined together.

A lump of copper is made up of only copper atoms. Water particles are made up of hydrogen atoms and oxygen atoms combined together. Scientists call this type of particle a molecule.

Hope this helps !!! Good luck!!! ;)

iogann1982 [59]3 years ago

5 0

Answer: Water is made out of 3 atoms, 2 hydrogens and 1 oxygen.

Therefor, there answer will be A.

Hope this helps! :D

-TanqR

(Please give me brainliest)

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An organic compound contains , , , and . Combustion of 0.1023 g of the compound in excess oxygen yielded 0.2587 g and 0.0861 g .

Kisachek [45]

The question displayed below shows the missing information which therefore completes the question.

An organic compound contains C, H, N and O. Combustion of 0.1023 g of the compound in excess oxygen yielded 0.2587 g of CO2 and 0.0861 g of H2O. A sample of 0.4831 g of the compound was analyzed for nitrogen by the Dumas method. The compound is first reacted by passage over hot: The product gas is then passed through a concentrated solution of to remove the. After passage through the solution, the gas contains and is saturated with water vapor. At STP, 38.9 mL of dry N2 was obtained. In a third experiment, the density of the compound as a gas was found to be 2.86 g/L at 127°C and 256 torr. What are the empirical and molecular formulas of the compound? (Enter the elements in the order: C, H, N, O.)

Answer:

the empirical formula = $\mathbf {C_3H_6O_{12}N}$

the molecular formula = $\mathbf {C_3H_6O_{12}N}$

Explanation:

From the given information:

$\bigg ( 0.2587 \ g \ of CO_2 \bigg) \times \dfrac{1 \ mol \ of CO_2}{44 \ of \ CO_2} \times \dfrac{1 \ mol \ of \ C}{1 \ mol \ of CO_2}$

$= 0.00588 \ mol \ of \ C \times \dfrac{12.01 \ g \ of \ C}{1 \ mol \ of \ C }$

= 0.0706g of C

$\bigg ( 0.0861\ g \ of H_2O \bigg) \times \dfrac{1 \ mol \ of H_2O}{18.02 \ g \ of \ H_2O} \times \dfrac{2 \ mol \ of \ H}{1 \ mol \ of H_2O}$

$=0.0096 \ mol \times \dfrac{1.008 \ g \ of \ H}{1 mol \ H}$

0.0097g of H

Given that N2 at STP = 1 atm, 273 K and V = 0.0389 L

PV = nRT

n = PV/RT

$n = \dfrac{1 \ atm \times 0.0389 \ of \ H_2}{0.0821 \ L.atm /mol.K \times 273 \ K }$

n = 0.00173 mol of N2

The oxygen in the sample = The total grams in sample - gram in H - gram in C

The oxygen in the sample = 0.1023 g - 0.0097 g - 0.706 g

The oxygen in the sample = 0.022 g of O

The number of moles of $O_2 = \dfrac{0.02}{16}$

= 0.001375 mol of O

$O \ in \ product = (0.00588 \ mol \ of \ C ) \times \dfrac{2 \ mol \ of \ O }{1 \ mol \ of \ C }+ \bigg ( 0.0096 \ mol \ of \ H ) \times \dfrac{1 \ mol \ of \ O }{1 \ mol \ of \ H}$

O in product = 0.02136 mol of O

∴

we are meant to divide the moles of each compound by the smallest number of moles; we have:

$C = \dfrac{0.00588}{0.00173} \simeq 3$

$H = 0.0096 = \dfrac{0.0096}{0.00173} \simeq 6$

$O = 0.0199= \dfrac{0.0199}{0.00173} \simeq 12$

$N = 0.00173= \dfrac{0.00173}{0.00173} \simeq 1$

Thus; the empirical formula = $\mathbf {C_3H_6O_{12}N}$

To estimate the molecular formula; we have:

$MM = \dfrac{dRT}{P}$

$MM = \dfrac{2.80 \ g/ L \times 0.0821 \ L.atm /mol.K \times 400 \ K }{0.337 \ atm}$

MM = 272.86 g/mol

Also; the molar mass of $\mathbf {C_3H_6O_{12}N}$ = 248 g/mol

∴

$= \dfrac{272.86 \ g/mol}{248 \ g/mol}$

$=1$

Thus; we can conclude that empirical formula as well as the molecular formula are the same.

6 0

3 years ago

What is the molarity of a solution that has 0.030 mil of NaCl dissolved in 1.2 L solution?

aliina [53]

Answer:

"Well, by definition,

molarity=

<u>moles of solute </u>

volume of solution"

Explanation:

THE LINES UNDER <u>moles of solute </u>MEANS ITS OVER volume of solution"

I THINK IM RIGHT PLZ NOT HATE ON ME IF IN WRONG

7 0

4 years ago

Suppose you wanted to dissolve 109 g of sodium carbonate in enough water to make 6.00 L of solution. What is the molarity of thi

kumpel [21]

Molarity

a. Na2CO3
Molar mass = 106 g/mol
n= 109 g / (106 g/mol) = 1.028 mol

b. 6.00L

c. M=n/V
M = 1.028 mol / 6.00 L
M= 0.1713 mol / L

Answer: The molarity of the sodium carbonate solution is 0.1713 mol/L

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4 years ago

An ideal gas contained in 5.0 liter chamber at a temperature of 37°C. If

kodGreya [7K]

Answer:

i am doing this in science also i would like to know if u know

Explanation:

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3 years ago

When adding sugar to tea, it was observed that the sugar kept dissolving. After a

a_sh-v [17]

The molecule of mixture cannot be seen hence, it will be considered as homogeneous mixture.

<h3>What is molecule?</h3>

A molecule is just a collection of more than two atoms bound together by chemical bonds; depending on the context, the phrase doesn't have to include ions that meet this requirement.

<h3>What is homogeneous mixture?</h3>

Solids, liquids, as well as gases, can all be homogeneous mixtures. Through, they have almost the same look and chemical makeup.

When sugar will be dissolved, the sucrose molecules get separated from one another. The materials that make up individual molecules stay together like sucrose molecules sucrose molecules, so the molecule will not break up.

Therefore mixture can be considered as molecule and homogeneous mixture.

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2 years ago

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