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gtnhenbr [62]
3 years ago
8

What is the pOH if the pH is 11?

Chemistry
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

3

Explanation:

14-11=3

- Hope that helps! Please let me know if you need further explanation.

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Sulfur hexafluoride, SF6, is a colorless, odorless, very unreactive gas. Calculate the pressure (in atm) exerted by 2.02 moles o
miss Akunina [59]

Answer:

9.15 atm

Explanation:

Ideal gas equation of state PV=nRT

P in hPa, V in L, n in mol, R is a constant which is 83.1 hpa*L/mol*k, T in kelvin.

Plug in all the number, and we will get:

P*6.21=2.02*83.1*343

P =9271.6(in hpa)=9.15 atm

8 0
2 years ago
What words can you spell isotherm periodic table
AlladinOne [14]

Explanation:

The periodic table of elements has a rich diverse number of elements. Every element on the table is arranged based on their atomic numbers into their respective groups and columns.

The coining of words from the table is done creatively by combining symbols of elements.

Here are some of the world list:

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learn more:

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5 0
3 years ago
In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg
makvit [3.9K]
Use the formula E=mc^2
energy given=<span>8.1 x 10^16 joules
</span>speed of <span>light = 3.00 × 10^8 m/s
</span>
plug in the values we'll get mass=<span>9.0 x 10-1 kg</span>

5 0
3 years ago
Read 2 more answers
How much heat energy is required to raise the temperature of 0.368 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co
Dmitriy789 [7]
23.0 + 60.0 = 83.0° C heat energy is required to raise
7 0
3 years ago
A cylinder with a moving piston expands from an initial volume of 0.350 L against an external pressure of 1.90 atm. The expansio
myrzilka [38]

Answer:

1.84 L

Explanation:

Using the equation for reversible work:

W = -P*(V_{2} - V_{1})

Where:

W is the work done (J) = -287 J.

Since the gas did work, therefore W is negative.

P is the pressure in atm = 1.90 atm.

However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K);  R = 0.0821 (L*atm)/(mol*K)

Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J

V_{1} is the initial volume = 0.350 L

V_{2} is the final volume = ?

Thus:

(-287 J)*0.00987 (L*atm)/J = -1.9 atm*(V_{2} - 0.350) L

V_{2} = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L

7 0
3 years ago
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