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3 years ago

Which equation is a point slope form equation for line AB ?

Mathematics

2 answers:

qaws [65]3 years ago

8 0

Answer: D . $((y+2)=-2(x-5)$

Step-by-step explanation:

The equation of a line passing through two points (a,b) and (c,d) in point-slope form is given by :-

$(y-d)=\dfrac{d-b}{c-a}(x-c)$

From the given graph ,it can be seen that the line is passing through two points A(1,6) and B(5,-2).

Then the equation for the line AB in point-slope form would be :-

$(y-(-2))=\dfrac{-2-6}{5-1}(x-5)$

$\Rightarrow\ (y+2)=\dfrac{-8}{4}(x-5)$

$\Rightarrow\ (y+2)=-2(x-5)$

Hence, the equation is a point slope form equation for line AB :

$(y+2)=-2(x-5)$

guapka [62]3 years ago

7 0

I believe the answer is D
y+2=-2(x-5)
-2*-5=10
y+2=-2x+10
-2 -2
y=-2x+8

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9. Find P(rolling 1 or 5) with one number cube.

marta [7]

Answer:

1/3

Step-by-step explanation:

There are 6 possible outcomes when rolling 1 die

1,2,3,4,5,6

P ( 1 or 5) = number of times 1 or 5 happens / total outcomes

= 2/ 6

= 1/3

6 0

4 years ago

Kay and Allen sell cell phones. Last month Kay sold 17 more cell phones than Allen. Together they both sold 117 cell phones. How

mrs_skeptik [129]

Answer:

Kay sold 67; Allen sold 50

Step-by-step explanation:

Let "a" represent the number of phones that Allen sold.

a + (a+17) = 117 . . . equation used to find the answer

2a = 100 . . . . . . . . subtract 17, collect terms

a = 50 . . . . . . . . . . divide by 2; the number Allen sold

a+17 = 67 . . . . . . . . Kay sold 17 more than Allen

5 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago

There are 1,000 grams in 1 kilogram. Nate is mailing a package that has a mass of 8,000 grams.

Anna007 [38]

Nate's package is 8 kilograms. This is because, if there are 1,000 grams in 1 kilogram, 8,000/ 1,000= 8 Therefore, the mass of his package is 8 kilograms.

Have a Merry Christmas!

5 0

3 years ago

Which could the confederate flag? hi guys

JulijaS [17]

Answer:

Step-by-step explanation:

but that was no a question but thanks

6 0

3 years ago