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Alexandra [31]
2 years ago
13

Let's suppose someone flips a fair coin three times. 1. How many outcomes are possible? [a] 2. What is the probability of gettin

g exactly one tail? Give as a fraction [b] 3. What is the probability of getting at most two tails? Give asa fraction [c]​
Mathematics
1 answer:
andrey2020 [161]2 years ago
7 0

Probability helps us to know the chances of an event occurring. There are 8 outcomes.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}

Let's suppose someone flips a fair coin three times.

1. The outcomes of the coins are,

  • HHH
  • HHT
  • HTH
  • HTT
  • TTH
  • THT
  • TTH
  • TTT

Therefore, there are 8 outcomes.

2. The probability of getting exactly one tail is,

P(X=1) = 2/8 = 1/4

3. The probability of getting at most two tails is,

P(X≤2) = P(X=1) + P(X+2) = 1/4 + 1/2 = 3/4

Learn more about Probability:

brainly.com/question/795909

#SPJ1

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Answer:

I can but not willing right now so sorry

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Step-by-step explanation:

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astra-53 [7]
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I hope this helps! Let me know if you have any questions :)
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Answer:

-25

Step-by-step explanation:

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2 years ago
What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?
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\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;n=12\\&#10;d=-10\\&#10;a_{12}=13&#10;\end{cases}&#10;\\\\\\&#10;a_{12}=a_1+(12-1)d\implies 13=a_1+(12-1)(-10)&#10;\\\\\\&#10;13=a_1-110\implies \boxed{123=a_1}

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