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Alexandra [31]
2 years ago
13

Let's suppose someone flips a fair coin three times. 1. How many outcomes are possible? [a] 2. What is the probability of gettin

g exactly one tail? Give as a fraction [b] 3. What is the probability of getting at most two tails? Give asa fraction [c]​
Mathematics
1 answer:
andrey2020 [161]2 years ago
7 0

Probability helps us to know the chances of an event occurring. There are 8 outcomes.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}

Let's suppose someone flips a fair coin three times.

1. The outcomes of the coins are,

  • HHH
  • HHT
  • HTH
  • HTT
  • TTH
  • THT
  • TTH
  • TTT

Therefore, there are 8 outcomes.

2. The probability of getting exactly one tail is,

P(X=1) = 2/8 = 1/4

3. The probability of getting at most two tails is,

P(X≤2) = P(X=1) + P(X+2) = 1/4 + 1/2 = 3/4

Learn more about Probability:

brainly.com/question/795909

#SPJ1

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Answer:

I did the math and got an answer of 17.5

Step-by-step explanation:

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3 years ago
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Answer:

303.3 ft

Step-by-step explanation:

16.3ft²÷2=8.15

then V = LWH/3

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3 years ago
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kirill115 [55]
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Determine dois números ímpares consecutivo cujo produto seja 195
miv72 [106K]
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We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78 
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3 years ago
How to find the zeros of f(x)=5(2x-5)(5x+4)
Elenna [48]
If xy=0 we assume x and y equal 0

so

the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that

0=2x-5
5=2x
5/2=x

0=5x+4
-4=5x
-4/5=x

zeroes at x=5/2 and -4/5
3 0
3 years ago
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