Answer:
x = 30
Step-by-step explanation:
here 50 is hypotenuse as it is opposite of 90 degree.
x and x + 10 are the two other smaller sides of a right angled triangle respectively.
using pythagoras theorem,
a^2 + b^2 = c^2
x^2 + (x + 10)^2 = 50^2
x^2 + x^2 + 20x + 100 = 2500
2x^2 + 20x + 100 = 2500
2x^2 + 20x + 100 - 2500 = 0
2x^2 + 20x - 2400 = 0
2(x^2 + 10x - 1200) = 0
x^2 + 10x - 1200 = 0
x^2 + (40 - 30) - 1200 = 0
x^2 + 40x - 30x - 1200 = 0
x(x + 40) - 30(x + 40x) = 0
(x + 40)(x - 30) = 0
either x + 40 = 0 OR x - 30 = 0
x = 0 - 40
x = -40
x - 30 = 0
x = 30
x = -40,30
since the length and distance is not measured in negative ur answer will be 30
credit goes to sreedevi102
thank u very much . At first i was wrong and giannathecookie i m really sorry
Answer:
A. 1:8
Step-by-step explanation:
We have been given that several students were asked to name the kinds of animals they saw in the past week at the park.
Dogs: 8
Cat: 2
Fish: 4
Lizard: 2
We are asked to find the ratio that compares the number of cats seen to the total number of animals seen.
Let us find total number of animal by adding each type of animals as:
We can see that the students saw 2 cats, so ratio of cats to total animals would be 
.
Dividing 2 and 16 by 2, we will get:
Therefore, the ratio 1:8 compares the number of cats seen to the total number of animals seen and option A is the correct choice.
Answer:
c. 18
Step-by-step explanation:
First, you would find the total sum of the 60 numbers. The average is always the sum of the numbers divided by the number of numbers.
35*18=630
15*10=150
Now we do not know how many numbers the last group has. However, we can find it out doing 60-35-15 to see how many numbers are left. There would be 10 numbers left
10*30=300
630+150+300=1080
1080/60=18
Hence, the answer is C(18)
Answer:
D.68 is greater than 112 because 68 is greater than the benchmark 12, and 112 is less than the benchmark 12.
9514 1404 393
Answer:
zero
Step-by-step explanation:
Dividing the second equation by -3, it becomes ...
x -3y = 7/3
Compared to the first equation, ...
x -3y = 5
we see that it is <em>inconsistent</em>. No values of the variables can satisfy both equations. There are no solutions.
