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iVinArrow [24]
3 years ago
14

What is the solution for the system of linear equations?

Mathematics
1 answer:
monitta3 years ago
6 0
The correct answer is A
Hope this helped :)
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eduardo works as an accountant for a consulting firm. he earns an annual salary of 68,090 and an annual bonus based of the firms
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Answer:

70.132,70

Step-by-step explanation:

68.090,00

+ 2.042,70

_________

70.132,70

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Please help ASAP it’s due tomorrow at 12
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Answer:

value of x is 22°

Step-by-step explanation:

It is 22 degrees because it is originally a right angle which is 90°. If you do 90-68 you would get 22. The reason you would subtract is because 68 is already used of the 90° angle. My explanation isn't that good.

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PLEASE HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Answer:

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Step-by-step explanation:

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3 years ago
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Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position
Ipatiy [6.2K]

Answer:

Part A)  Not collide

Part B)  k = 4

Part C)  Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

<u><em>Position of particle A:-</em></u>

x(t)=5t-5

y(t)=2t-k

<em><u>Position of particles B:-</u></em>

x(t)=4t

y(t)=t^2-2t+1

Part A)  For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, (4t,t^2-2t-1)

If both collides then x and y coordinate must be same

Therefore,

  • For x-coordinate:

5t - 5 = 4t    

       t = 5

  • For y-coordinate:

2t+6=t^2-2t-1

t^2-4t-7=0

t=-1.3,5.3

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

  • For x-coordinate:

5t - 5 = 4t    

       t = 5

  • For y-coordinate:

2t-k=t^2-2t-1

Put t = 5

10-k=25-10-1

k=4

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, \dfrac{dA}{dt}

\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}

\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4

Speed of particle B, \dfrac{dB}{dt}

\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}

\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}

At t = 5

\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2

Hence, Particle B moves faster than particle A

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3 years ago
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I don't understand the question but if I think what I think the question is asking me I would say 2 feet
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