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HACTEHA [7]
3 years ago
14

Ways to accelerate an object

Physics
1 answer:
inysia [295]3 years ago
4 0
Increasing speed, decreasing speed, or a change in direction
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For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C

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A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

7 0
3 years ago
If white light falls on a piece of white paper in a dark room, the paper appears white to the eye. This is because the paper ref
Sindrei [870]
It would appear Red because as stated above, the paper reflects all the colors of light that fall on it.
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Which of the following factors influence the electrical resistance of a circuit?
stealth61 [152]
-- material and thickness of the interconnecting wires;

-- number, type, and configuration of all the devices
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the points that connect to the battery;

-- quality of the connections at the points where
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5 0
3 years ago
The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 5.00 T/s. Part A) What is the electric field str
Veronika [31]

Answer:

(A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 3.75\times10^{-2}\ V/m.

Explanation:

Given that,

Magnetic field = 2.0 T

Diameter = 5.0 cm

Rate of decreasing in magnetic field = 5.00 T/s

(A). We need to calculate the electric field strength inside the solenoid at a point on the axis

Using formula of electric field inside the solenoid

E=\dfrac{r}{2}|\dfrac{dB}{dt}|

Electric field on the axis of the  solenoid

Here, r = 0

E=\dfrac{0}{2}\times5.00

E = 0

The electric field strength inside the solenoid at a point on the axis is zero.

(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis

Using formula of electric field inside the solenoid

E=\dfrac{r}{2}|\dfrac{dB}{dt}|

E=\dfrac{1.50\times10^{-2}}{2}\times|5.00|

E=0.0375= 3.75\times10^{-2}\ V/m

Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 3.75\times10^{-2}\ V/m.

4 0
4 years ago
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