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Vika [28.1K]
4 years ago
5

A hummingbird can a flutter its wings 4800 times per minute what is the frequency of wing flutters per second

Physics
2 answers:
Scilla [17]4 years ago
7 0

the answer i got is 80 i hope this helpss!!!!

Arlecino [84]4 years ago
7 0

Answer:

The frequency of wing flutters per second is 80.

Explanation:

Frequency is defined as the number of waves that passes a given point per second. It is expressed in Hertz that second inverse.

1 Hertz = 1 s^{-1}

Number of times wings fluttered by hummingbird = 4800 min^{-1}

1 minute = 60 seconds

Frequency wing flutters per second = F

F = 4800 min^{-1}=\frac{4800}{60 s}=80 s^{-1}

The frequency of wing flutters per second is 80.

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a.

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W=F\cos\theta\cdot d

where F is the magnitude of the force, theta is the angle between them and d is the distance.

The problen gives the following data:

The magnitude of the force 750 N.

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The distance, 26 m.

Plugging this in the formula we have:

\begin{gathered} W=\left(750\right)\left(\cos25\right)\left(26\right) \\ W=17673 \end{gathered}

Therefore the work done is 17673 J.

b)

The power is given by:

P=\frac{W}{t}

the problem states that the time it takes is 6 s. Then:

\begin{gathered} P=\frac{17673}{6} \\ P=2945.5 \end{gathered}

Therefore the power is 2945.5 W

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<em>a) increases</em>

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If this slope intersects the graph at x-axis, it means that the body has 0 velocity and has become still. After that, if the line enters in the negative region, it means that its velocity is started to increases again, but the body is movinging in the opposite direction (negative direction)

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3 years ago
A 500-N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area
weqwewe [10]

Answer:

W₂= 10000 N

Explanation:

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\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

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Data

W₁ = weight sits on the small piston

F₁ = W₁= 500 N

A₁ = 2.0 cm²

A₂ = 40 cm²

Calculation of the weight  (W₂) can the large piston support

We replace data in the equation (1)

F_{2} = \frac{(500)*(40) }{2}

F₂ = 10000 N

W₂= F₂= 10000 N

6 0
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