D is the most reasonable as the other 3 answers are improbable.
Answer:
about 6
1 is 90
2 is 35 same with 3
4 is 28
5 is 62
Step-by-step explanation:
Answer:
If a person is randomly selected from this group, the probability that they have both high blood pressure and high cholesterol is P=0.25.
Step-by-step explanation:
We can calculate the number of people from the sample that has both high blood pressure (HBP) and high cholesterol (HC) using this identity:
![N(\text{HBP or HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP and HC})\\\\\\ N(\text{HBP and HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP or HC})\\\\\\ N(\text{HBP and HC})=15+25-30=10](https://tex.z-dn.net/?f=N%28%5Ctext%7BHBP%20or%20HC%7D%29%3DN%28%5Ctext%7BHBP%7D%29%2BN%28%5Ctext%7BHC%7D%29-N%28%5Ctext%7BHBP%20and%20HC%7D%29%5C%5C%5C%5C%5C%5C%20N%28%5Ctext%7BHBP%20and%20HC%7D%29%3DN%28%5Ctext%7BHBP%7D%29%2BN%28%5Ctext%7BHC%7D%29-N%28%5Ctext%7BHBP%20or%20HC%7D%29%5C%5C%5C%5C%5C%5C%20N%28%5Ctext%7BHBP%20and%20HC%7D%29%3D15%2B25-30%3D10)
We can calculate the probability that a random person has both high blood pressure and high cholesterol as:
![P(\text{HBP and HC})=\dfrac{10}{40}=0.25](https://tex.z-dn.net/?f=P%28%5Ctext%7BHBP%20and%20HC%7D%29%3D%5Cdfrac%7B10%7D%7B40%7D%3D0.25)
Ax^2 + bx + c
multiply the "a" and "c" coefficient
= ac
factor "ac" into a pair of numbers that adds to equal "b"
replace "bx" in the expression with factor pair
group terms and factor
* example problem:
2x^2 + 13x + 6
ac
2*6=12
factor pairs of 12
1*12 = 12
3*4=12
6*2=12
** The factor pair 1 and 12 add to make 13
replace 13x with (x+12x)
2x^2 + x + 12x + 6
group similar terms
(2x^2 + 12x) + (x + 6)
factor
2x(x + 6) + (x + 6)
The same parenthesis (x + 6) can be factored further by combining the outside multipliers 2x and 1
= (2x + 1)(x + 6)
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