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k0ka [10]
3 years ago
11

PLEASE HELP!!!

Mathematics
1 answer:
nevsk [136]3 years ago
3 0
A. False. The slope is actually -1/2. Each time y goes down by 1, x increases by 2. 

B. True. We can use the slope formula to further confirm the slope is -1/2

C. False. The slope is the same throughout the line. So slope of OA = slope of AB. The slope throughout the line is -1/2.

D. False. Same reason as choice C

------------------------------------

Final Answer: Choice B

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A deck of cards contains 5 black cards numbered 5 to 9 and 5 red cards numbered 1 to 5. How many 6-card hands having 4 black car
tester [92]

Answer:

50

Step-by-step explanation:

4 black cards = 5C4 = 5

2 red cards = 5C2 = 10

5 x 10 = 50

5 0
3 years ago
18x^2+69x+60 Factor the expression
Kipish [7]
3(3x+4)(2x+5)

Because you factor out the 3 and then factor 6x^2+23x+20
That becomes (6x^2+8x)+(15x+20)
Factor out a two from the left and five from the right.
That makes 2x(3x+4) + 5(3x+4)
That becomes (3x+4)(2x+5)
Then put the three back in front.
6 0
4 years ago
11. A bank teller has a total of 124 bills in five-dollar bills and ten-dollar bills. The total value of the
Sergeu [11.5K]
From my understanding, there are 124 5 dollar bills which would equal $620.

The total money of the value is $840 then you would subtract. $840-$620=$220.

Divide that by ten so, $220/10= 22.

She has 22 ten dollar bills.
7 0
3 years ago
: In Ms. Perron’s class, 40% of the students are boys. There are 10 boys in the class. What is the total number of students in M
ruslelena [56]
<h3>Total number of students in Ms. Perron’s class is 25</h3>

<em><u>Solution:</u></em>

In Ms. Perron’s class, 40% of the students are boys

There are 10 boys in the class

Let "x" be the total number of students in Perron class

From given,

40 % of total students are boys

Therefore,

40 % of x = 10

\frac{40}{100} \times x = 10\\\\40x = 1000\\\\x = 25

Thus total number of students in Ms. Perron’s class is 25

7 0
3 years ago
F(x)= 9-x^2, x ≥ 0. f^-1(x)=??
julia-pushkina [17]
y=9-x^{2},\ x\ge0

Reverse x and y:
x=9-y^{2},\ y\ge0
Solve for y:
x=9-y^{2}
\rightarrow y^{2}=9-x
\rightarrow y=\sqrt{9-x} since y\ge0
7 0
3 years ago
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