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DedPeter [7]
3 years ago
9

A deck of cards contains 5 black cards numbered 5 to 9 and 5 red cards numbered 1 to 5. How many 6-card hands having 4 black car

ds and 2 red cards can be dealt
Mathematics
1 answer:
tester [92]3 years ago
5 0

Answer:

50

Step-by-step explanation:

4 black cards = 5C4 = 5

2 red cards = 5C2 = 10

5 x 10 = 50

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tip = 48.28

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6 0
3 years ago
What is 40 meters in 8 seconds?
Basile [38]

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4 0
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Anna [14]

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False.

Step-by-step explanation:

6 0
3 years ago
Does anyone know this? <br> Will mark brainliest !!!!
stich3 [128]

Answer:

x=4

y=4√5

Step-by-step explanation:

Set up 3 right triangles and mark their respective angles. The largest will have sides (in typical a,b,c[hypotenuse] order) y, z, and 10. The middle 8, x, and y. The smallest x,  2, and z.

Then since they are all similar triangles, using the midde and smaller triangles, set up the proportionin which both A sides when divided are equal to the B sides.

So 8/x = x/2

Cross multiply and get 16=x^2.

The  square root of 16 is 4, so x is 4.

Then using the larger and middle triangles, do the same for the A and C sides.

So y/8 = 10/y.

Cross multiply and get 80=y^2.

Find the square root of it, which since it doesn't have a perfect square, you use a calculator or the whatever theorem and get √4*4*5 or simply 4√5.

So x = 4 and y = 4√5

5 0
3 years ago
2a2b3 and -4a2b3 are like terms.<br> a. True<br> b. False
Trava [24]
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Your final answer is a. True.
4 0
3 years ago
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