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DedPeter [7]
3 years ago
9

A deck of cards contains 5 black cards numbered 5 to 9 and 5 red cards numbered 1 to 5. How many 6-card hands having 4 black car

ds and 2 red cards can be dealt
Mathematics
1 answer:
tester [92]3 years ago
5 0

Answer:

50

Step-by-step explanation:

4 black cards = 5C4 = 5

2 red cards = 5C2 = 10

5 x 10 = 50

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Answer:

(a) The distribution of the sample proportion is Normal distribution.

(b) The probability that in this sample of 150 households that more than 50% own a 4K television is 0.00012.

Step-by-step explanation:

We are given that in the United States, 35% of households own a 4K television.

Suppose we take a random sample of 150 households.

<em>Let </em>\hat p<em> = sample proportion of households who own a 4K television.</em>

The z-score probability distribution for sample proportion is given by;

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where, \hat p = sample proportion

     p = population proportion of households own a 4K television = 35%

     n = sample of households = 150

(a) The distribution of the sample proportion is related to the Normal distribution.

(b) Probability that in this sample of 150 households more than 50% own a 4K television is given by = P( \hat p > 0.50)

    P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{ 0.50-0.35}{\sqrt{\frac{0.50(1-0.50)}{150} } } ) = P(Z > 3.67) = 1 - P(Z \leq 3.67)

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<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 3.67 in the z table which has an area of 0.99988.</em>

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