Mei does 6 problems in 18 minutes. How many can she complete in 12 minutes

1 answer:

5 0

Do cross multiplication

6 = x
18 12

Now cross multiply

(6)(12) = (18)(x)

72 = 18x

Divide both sides by 18

72 = 18x
18 18

4 = x

So tMei can complete 4 problems in 12 minutes.

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Which ratio is equivlant to 3:4

Crank

Answer:

There is multiple. You didnt give options so heres all of them.

Step-by-step explanation:

6 : 8 9 : 12 12 : 16 15 : 20 18 : 24 21 : 28 24 : 32 27 : 36 30 : 40 33 : 44 36 : 48 39 : 52 42 : 56 45 : 60 48 : 64 51 : 68 54 : 72 57 : 76 60 : 80 63 : 84 66 : 88 69 : 92 72 : 96 75 : 1007 8 : 104 81 : 108 84 : 112 87 : 116 90 : 120 93 : 124 96 : 128 99 : 132 102 : 136 105 : 140 108 : 144 111 : 148 114 : 152 117 : 156 120 : 160 123 : 164 126 : 168 129 : 172 132 : 1761 35 : 180 138 : 184 141 : 188 144 : 192 147 : 196 150 : 200 153 : 204 156 : 208 159 : 2121 62 : 216 165 : 220 168 : 224 171 : 228 174 : 232 177 : 236 180 : 240 183 : 244 186 : 248 189 : 252 192 : 256 195 : 260 198 : 264 201 : 268 204 : 272 207 : 276 210 : 280 213 : 284 216 : 288 219 : 292 222 : 296 225 : 300 228 : 304 231 : 308 234 : 312 237 : 316 240 : 320 243 : 324246 : 328249 : 332252 : 336255 : 340258 : 344261 : 348264 : 352267 : 356270 : 360273 : 364276 : 368279 : 372282 : 376285 : 380288 : 384291 : 388

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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t

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Answer:

$\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24$

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of $\triangle ACD$ and the hypotenuse of $\triangle ADB$ .

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}$

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is $\angle CAD$ . The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

$\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}$

Now use this value in the Law of Sines to find AD:

$\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}$

Recall that $\sin 45^{\circ}=\frac{\sqrt{2}}{2}$ and $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ :

$AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}$

Now that we have the length of AD, we can find the length of AB. The right triangle $\triangle ADB$ is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio $x:x\sqrt{3}:2x$ , where $x$ is the side opposite to the 30 degree angle and $2x$ is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent $2x$ in this ratio and since AB is the side opposite to the 30 degree angle, it must represent $x$ in this ratio (Derive from basic trig for a right triangle and $\sin 30^{\circ}=\frac{1}{2}$ ).