2p/3 - 12 = -2 A: 15 B: 7 C: 17 D: -21

some of the steps in the derivation of the quadratic formula are shown. step 3: –c b^2/4a=a(x^2 b/ax b^2/4a62) step 4a: –c b^2/4

wel

-converting to a common denominator

The terms -c of the left side was converted to -4ac/4a to have the same denominator of b^2/4a.

3 0

3 years ago

Read 2 more answers

(3) Find the value of x.

jek_recluse [69]

Answer:

x=4

Step-by-step explanation:

since triangles are proportional by 2:1, then:

16/2=3x-4

8=3x-4

3x=12

x=4

3 0

2 years ago

Solve for x 6x²+2x-12

dem82 [27]

Answer:

Step-by-step explanation:

Solving for x means you have to factor. First factor out the GCF of 2 to get:

$2(3x^2+x-6)$ and now we'll factor using the regular old method of ac and then factoring by grouping. In our polynomial, a = 3, b = 1, c = -6. Therefore, a times c is 3 * -6 which is -18. We need some combinations of the factors of 18 that will add to give us 1, the b term in the middle. The factors of 18 are:

1, 18

2, 9

3, 6 and that's it. Hm...it seems that won't work, so let's throw this into the quadratic formula, going back to the original and a = 6, b = 2 and c = -12:

$x=\frac{-2+/-\sqrt{2^2-4(6)(-12)} }{2(6)}$ and

$x=\frac{-2+/-\sqrt{4+288} }{12}$ and

$x=\frac{-2+/-\sqrt{292} }{12}$ and

$x=\frac{-2+/-\sqrt{4*73} }{12}$ and

$x=\frac{-2+/-2\sqrt{73} }{12}$ which finally simplifies to

$x=\frac{-1+/-\sqrt{73} }{6}$ No wonder that didn't factor using the traditional method of factoring! We could have found that out by finding first the value of the discriminant, but oh well!

8 0

2 years ago

Number 13 I’ll reward you brainiest!!

Luden [163]

The answer is 3 bozo open ur eyes

7 0

2 years ago

Read 2 more answers

A cat keeps eating to gain weight while a dog keeps doing exercise.Later, the cat's weight increases by 20% and the dog's weight

lesya [120]

Answer:

Step-by-step explanation:

We will call the dog's original weight d and the cat's c. according to the problem 1.2c=.9d

1.2c is the cat's weight increased by 20% and .9d is the dog's weight decreased by 10% Now we just solve this with algebra for the dog's original weight.

1.2c=.9d

(1.2/.9)c = d

(4/3)c = d

Now, this tells us that the dog's original weight was 4/3 of the cat's.or about 33.33% larger

It kinda looks like the question is then asking what the cat's current weight is in comparison to the dog's original. If that's the case we need just one more step. We want the dog's original weight and the cat's current weight in terms of the same variable. Well, we have that.

Current cat = 1.2c or 6/5, since we have the other in fractional form.

original dog = (4/3)c

Now, what do we multiply the first to get to the second? Well, we need common denominators. 15 is the lcm of 3 and 5, so we'll use that.

6/5 = 18/15 and 4/3 = 20/15

Nowwe want to know what we have to multiply 18 by to get to 20. some algebra will find that.

18x=20

x = 20/18

x = 10/9

that's about 1.11, so the dog's original weight is about 11% higher than the cat's current weight.

Hopefully that's the answer it wanted, if not or if there is something you didn't understand let me know.

7 0

3 years ago