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3 years ago

Which of the following best describes the group development pattern known as punctuated equilibrium?

Business

2 answers:

Leona [35]3 years ago

8 0

Answer:

b. At the midpoint of the project, members realize that their behavior pattern must change in order to complete the project on time.

Explanation:

The punctuated-equilibrium model of group development is states that after a long periods of no change, members a of group usually have no choice than to move forward during bursts of change. At this point, it known to the members that the only way to complete a given task is for them to alter the pattern of the behavior.

Therefore, the correct option is b. At the midpoint of the project, members realize that their behavior pattern must change in order to complete the project on time.

melisa1 [442]3 years ago

4 0

Answer:

The answer is B: At the midpoint of the project, members realize that their behavior pattern must change in order to complete the project on time.

Explanation:

Punctuated equilibrium is a concept in both biology and business where long periods of relative stability are often followed by growth spurts.

The punctuated-equilibrium model argues that groups usually move forward during bursts of change after going for long periods without change.

In the answer B, this concept is captured as group members of a project realise somewhere at the midpoint, that their behavior pattern must change in order to complete the project on time.

This shows that a period of relative stability was observed and then a short period of growth will be observed during the project lifecycle. This agrees with the development pattern known as punctuated equilibrium.

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Answer:

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2 years ago

In a reorder point problem where both demand and lead time are variable, demand averages 200 units per day with a daily variance

Romashka [77]

Answer:

~ 1561.235

Explanation:

Given :

$Z=1.645$

$d = 200\ \\variance =64$

Standard deviation can be determined by the $\sqrt{variance }$

Standard deviation=SD

= $\sqrt{64}\ =\ 8$

$LT = 6\$

σ = 8

Now using the formula

$R\ =\ d \ *\ LT\ +Z\ \sqrt{LT^{2}\ +SD^{2} \ +\ d\ \sigma\ ^{2} } \\\\Putting\ the\ respective\ value\ we\ get \\R=200 * 6 + 1.645\sqrt{6 * 8^2 + 200 *1^2}$

R=1561.235

~ 1561.235

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