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sveta [45]
3 years ago
10

El punto de fusión del plomo es de 327 °C y su punto de ebullición, de 1750 °C. a) ¿En qué estado se encontrará un trozo de plom

o calentado hasta 325 °C?
Physics
1 answer:
Temka [501]3 years ago
6 0

Answer:

01001101 01100101 00100000 01101100 01100001 00100000 01110011 01110101 01100100 01100001 00100000 01110100 01110010 01100101 01110011 00100000 01100011 01101111 01101010 01101111 01101110 01100101 01110011

Explanation: traducelo a binario :)

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What 2 things need to be known about an object in order to determine its kinetic energy?
NikAS [45]
I believe the answer is the mass of the object and the speed at which it is moving. 
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Which diagram represents deposition?
Vera_Pavlovna [14]

Your answer will be gas

3 0
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28.25 mL, three signicant digits
Mazyrski [523]

Answer:3) variable affinities (stickiness) for something it is running past. Physical ... -measurement number (significant digits) unit (such as inches) -Significant ... Mass 1 oz. 28.25 g. Relations Between English and Metric Units Mass 1 dram. 1.772 g ... -graduated cylinder has an error of about 1% (± 0.1 mL in 10 mL). -Volumetric

Explanation:

3 0
2 years ago
Read 2 more answers
If the resultant of two velocity vectors of equal magnitude is also of the same magnitude, then which statement must be correct?
Tamiku [17]

The correct option is C) The angle between the vectors is 120°.

Why?

We can solve the problem and find the correct option using the Law of Cosine.

Let A and B, the given two sides and R the resultant (sum),

Then,

R=A=B

So, using the law of cosines, we have:

R^{2}=A^{2}+B^{2}+2ABCos(\alpha)\\ \\A^{2}=A^{2}+A^{2}+2*A*A*Cos(\alpha)\\\\0=A^{2}+2*A^{2}*Cos(\alpha)\\\\Cos(\alpha)=-\frac{A^{2}}{2*A^{2}}=-\frac{1}{2}\\\\\alpha =Cos(-\frac{1}{2})^{-1}=120\°

Hence, we have that the angle between the vectors is 120°. The correct option is C) The angle between the vectors is 120°

Have a nice day!

4 0
2 years ago
Find the cost of excavating a space 84 ft long, 42 ft wide, and 9 ft deep at a cost of $39/yd3. (simplify your answer completely
m_a_m_a [10]

The cost of excavating a space of 84 ft long, 42 ft wide, and 9 ft deep is $45864

Information about the problem:

  • Space long= 84 ft
  • Space wide= 42 ft
  • Space deep= 9 ft
  • Cost by yard3 = $39/yd3
  • Total cost= ?

To solve this problem, we have to state the equation using the information of the problem:

Calculating the volume of the total space:

space volume = space long * space wide * space deep

space volume = 84 ft * 42 ft * 9 ft

space volume = 31752 ft3

By converting the volume from ft3 to yd3, we have:

31752 ft3 * (0,037037 yd3 / 1 ft3) = 1176 yd3

Calculating the cost of excavating the volume space:

Total cost = space volume * cost by yard3

Total cost = 1176 yd3 * $39/yd3

Total cost = $45864

<h3>What is volume?</h3>

It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.

Learn more about volume at: brainly.com/question/12628341

#SPJ4

4 0
1 year ago
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