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kap26 [50]
2 years ago
15

Which statement defines an ore? Rock broken down to become part of the topsoil. Rock dug out from the earth to use in constructi

on. Rock dug out from the deep inside earth and refined. Rock exposed as a result of loss of topsoil.
Physics
2 answers:
Anika [276]2 years ago
5 0

Rock dug out from the deep inside earth and refined.

Explanation:

Ores are usually rocks dug out from deep within the earth and refined.

An ore is an aggregate of metalliferous minerals with gangue that can be won at profit under current economic conditions.

Ores are rocks and rocks can be ores if they contain viable economic minerals.

They are usually naturally formed and they contain different minerals.

For example cassiterite is a known ore of tin.

Learn more:

Rocks brainly.com/question/2817889

#learnwithBrainly

Ivanshal [37]2 years ago
5 0

Answer:

C.

Explanation:

According to E2020, the correct answer to this problem is C. Rock dug out from the deep inside earth and refined.

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A bead slides without friction around a loop the-loop. The bead is released from a height of 17.6 m from the bottom of the loop-
solong [7]

Answer:

 N₁ = 393.96 N   and  N = 197.96 N

Explanation:

In This exercise we must use Newton's second law to find the normal force. Let's use two points the lowest and the highest of the loop

Lowest point, we write Newton's second law n for the y-axis

          N -W = m a

where the acceleration is ccentripeta

          a = v² / r

           

          N = W + m v² / r

          N = mg + mv² / r

         

we can use energy to find the speed at the bottom of the circle

starting point. Highest point where the ball is released

           Em₀ = U = m g h

lowest point. Stop curl down

           Em_{f} = K = ½ m v²

           Emo = Em_{f}

           m g h = ½ m v²

           v² = 2 gh

we substitute

             N = m (g + 2gh / r)

            N = mg (1 + 2h / r)

let's calculate

          N₁ = 5 9.8 (1 + 2 17.6 / 5)

          N₁ = 393.96 N

headed up

we repeat the calculation in the longest part of the loop

          -N -W = - m v₂² / r

            N = m v₂² / r - W

             N = m (v₂²/r  - g)

we seek speed with the conservation of energy

           Em₀ = U = m g h

final point. Top of circle with height 2r

             Em_{f} = K + U = ½ m v₂² + mg (2r)

              Em₀ =   Em_{f}

            mgh = ½ m v₂² + 2mgr

             v₂² = 2 g (h-2r)

we substitute

            N = m (2g (h-2r) / r - g)

            N = mg (2 (h-r) / r 1) = mg (2h/r  -2 -1)

             N = mg (2h/r  - 3)

            N = 5 9.8 (2 17.6 / 5 -3)

            N = 197.96 N

Directed down

3 0
3 years ago
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