Answer:
a)
b)
Explanation:
From the question we are told that:
Distance between wires
Wire 1 current
Wire 2 current
a)
Generally the equation for Force on due to
is mathematically given by
Where
B_2=Magnetic field current by
Therefore
b)
Generally the equation for Force on due to
is mathematically given by
Where
B_1=Magnetic field current by
Therefore
Answer:
the frequency of the oscillation is 1.5 Hz
Explanation:
Given;
mass of the spring, m = 1500 kg
extention of the spring, x = 5 mm = 5 x 10⁻³ m
mass of the driver = 68 kg
The weight of the driver is calculated as;
F = mg
F = 68 x 9.8 = 666.4 N
The spring constant, k, is calculated as;
k = F/m
k = (666.4 N) / (5 x 10⁻³ m)
k = 133,280 N/m
The angular speed of the spring is calculated;
The frequency of the oscillation is calculated as;
ω = 2πf
f = ω / 2π
f = (9.426) / (2π)
f = 1.5 Hz
Therefore, the frequency of the oscillation is 1.5 Hz