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kap26 [50]
3 years ago
15

Which statement defines an ore? Rock broken down to become part of the topsoil. Rock dug out from the earth to use in constructi

on. Rock dug out from the deep inside earth and refined. Rock exposed as a result of loss of topsoil.
Physics
2 answers:
Anika [276]3 years ago
5 0

Rock dug out from the deep inside earth and refined.

Explanation:

Ores are usually rocks dug out from deep within the earth and refined.

An ore is an aggregate of metalliferous minerals with gangue that can be won at profit under current economic conditions.

Ores are rocks and rocks can be ores if they contain viable economic minerals.

They are usually naturally formed and they contain different minerals.

For example cassiterite is a known ore of tin.

Learn more:

Rocks brainly.com/question/2817889

#learnwithBrainly

Ivanshal [37]3 years ago
5 0

Answer:

C.

Explanation:

According to E2020, the correct answer to this problem is C. Rock dug out from the deep inside earth and refined.

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If a Ferrari, with an initial velocity of 14m/s, accelerates at a rate of 60
ss7ja [257]

Answer:

254

Explanation:

use the formula "final Velocity- initial velocity / time = acceleration"

so "X - 14 /4 = 60"

60 x 4 = X - 14

240 +14 = X

X = 254

8 0
2 years ago
Read 2 more answers
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Ludmilka [50]

Answer:

Force applied to stop the car = 1,250 N

Explanation:

Given:

Mass of car (M) = 1,000 kg

Initial velocity (U) = 20 m/s

Final velocity (V) = 0 m/s

Distance (S) = 160 m

Find:

Force applied to stop the car.

Computation:

v^2 = u^2 + 2as\\\\0^2=20^2+2(a)(160)\\\\0=400+320(a)\\\\Acceleration = a = -1.25m/s^2\\\\Force = ma \\\\Force= 1,000(1.25)\\\\Force = 1,250 N

Force applied to stop the car = 1,250 N

7 0
2 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
shtirl [24]

Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m

Explicación:

Dado lo siguiente:

Altura desde la cual se cae el cuerpo = 120 m

Tiempo (t) = 2.5s

A.) La velocidad que toma:

El cuerpo cayó desde una altura;

velocidad inicial (u) = 0

Para calcular v:

V = u + en

Donde a = aceleración debido a la gravedad = 9.8m / s

v = 0 + (9.8) (2.5)

v = 24.5 m / s

B) Cuánto ha disminuido.

Usando la ecuación de movimiento:

S = ut + 0.5at ^ 2

Donde S = distancia

S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)

S = 0 + 0.5 (9.8) (6.25)

S = 30.625 m

Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m

C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m

5 0
3 years ago
A 50kg skater at rest on a frictionless rink throws a 2kg ball, giving the ball a velocity of 10m/s. Which statement describes t
Andreas93 [3]

0.4m/s in the opposite direction of the ball.

3 0
3 years ago
What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ
borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

\omega = \sqrt{\frac{k}{m}}

now we have

\omega = \sqrt{\frac{k}{1200}}

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

a = \omega^2 A

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

\frac{1}{2}mv^2 = \frac{1}{2}kA^2

here we know that

v = 85 km/h

v = 85 \times\frac{1000}{3600} = 23.61 m/s

now we have

(1200)(23.61^2) = kA^2

A^2 = \frac{6.68 \times 10^5}{k}

now from above equation of acceleration we have

5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}

5.0(9.81) = \sqrt{k}(0.68)

k = 5178.8 N/m

6 0
3 years ago
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