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2 years ago

Due today HELP HELP HELP

Physics

1 answer:

Anna [14]2 years ago

5 0

Vas happenin!

Independent variable : amount of water each day

Dependent variable: water on the windsill

Hypotheses: Ben wants to try by adding water each day to two different places. Will that work? Will that effect the water?

Hope this helps you out

*smiles*

-Zayn Malik

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HELP!!! I have no idea how to calculate this.

stiks02 [169]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the kinematics of a body.

Since, we know that Velocity = Distance / time

hence, V = 20/5 = 4 m/s

hence the velocity of the RC car is 4 m/s westwards direction.

4 0

2 years ago

A water balloon is hovering directly above the line join points ANB which are 4.6 km apart if the angles of elevation to the bal

Anna35 [415]

Answer:

Drawing the triangle:

H / x = tan 52.2 = 1.29

H / (4.6 - x) = tan 28.8 = .550

H = 1.29 x

H = .55 * 4.6 - .55 x

1.84 x = 2.53 combining equations

x = 1.38

4.6 - 1.38 = 3.22

Total base of triangle = 1.38 + 3.22 = 4.6

H / x = tan 52,2 = 1.29

H = 1.29 * 1.38 = 1.78 height of triangle

Check:

1.78 / 3.22 = tan 28.9

This agrees with the given value of 28.8

7 0

1 year ago

You connect five identical resistors in series to a battery whose EMF is 12.0 V and whose internal resistance is negligible. You

neonofarm [45]

Answer:

Explanation:

Total resistance in the circuit

= EMF / current in the circuit

= 12 / .969

= 12.383 ohm

This resistance consists of 5 identical resistances in series

resistance of each resistor

= 12.383 / 5

= 2.476 ohm .

potential difference on each

= current x resistance of each

= .969 x 2.476

= 2.399 V

= 2.4 V

4 0

3 years ago

A typical running track is an oval with 74-mm-diameter half circles at each end. A runner going once around the track covers a d

lisabon 2012 [21]

The centripetal acceleration a is 4.32 $\times$ 10^-4 m/s^2.

<u>Explanation:</u>

The speed is constant and computing the speed from the distance and time for one full lap.

Given, distance = 400 mm = 0.4 m, Time = 100 s.

Computing the v = 0.4 m / 100 s

v = 4 $\times$ 10^-3 m/s.

radius of the circular end r = 37 mm = 0.037 m.

centripetal acceleration a = v^2 / r

= (4 $\times$ 10^-3)^2 / 0.037

a = 4.32 $\times$ 10^-4 m/s^2.

6 0

2 years ago