<span>12-50t=70t, t= 0.1h = 6 minutes.</span>
<span>The diver is heading downwards at 12 m/s
Ignoring air resistance, the formula for the distance under constant acceleration is
d = VT - 0.5AT^2
where
V = initial velocity
T = time
A = acceleration (9.8 m/s^2 on Earth)
In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m)
So let's substitute the known values and solve for T
d = VT - 0.5AT^2
-7 = 2.5T - 0.5*9.8T^2
-7 = 2.5T - 4.9T^2
0 = 2.5T - 4.9T^2 + 7
We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164.
Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So
V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s
V = 2.5 m/s - 14.47706141 m/s
V = -11.97706141 m/s
So the diver is going down at a velocity of 11.98 m/s
Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point.
V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s)
V = 2.5 m/s - (-9.477061409 m/s)
V = 2.5 m/s + 9.477061409 m/s
V = 11.97706141 m/s
And you get the exact same velocity, except it's the opposite sign.
In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
<u>Mass</u>
- Mass is measured in kilograms.
- Mass does not change when gravity changes.
- Mass is the amount of matter in something.
<u>Weight</u>
- Before I answer, we have to know weight formula. Weight = mass × acceleration due to gravity.
- Therefore, weight is measured in Newtons.
- Weight changes when gravity changes. This is because weight is dependent on acceleration due to gravity.
- Weight is a gravitational force.
Hope you could understand.
If you have any query, feel free to ask.
Answer:
he tension in an elevator cable is 10,000 N. The elevator itself has a mass of 500 kg.
Explanation:
Answer:
ε₂ =2.63 V
Explanation:
given,
M = 0.0034 H
I (t) = I₀ sin (ωt)
I (t) = 5.4 sin (143 t)
magnitude of the induced emf in the second coil
ε₂ =
ε₂ =
for maximum emf
cos (143 t) = 1
ε₂ =
ε₂ =2.63 V
