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Marta_Voda [28]
3 years ago
14

A brand new filled jar of salsa is 11 cm tall and a has a radius of 6 cm. Kelly eats some of the salsa and the salsa in the jar

is now 6 cm high.
Approximately how much salsa did Kelly eat?
Round your final answer to the nearest whole number.
188 cm³
565 cm³
679 cm³
1244 cm³
Mathematics
2 answers:
Sonbull [250]3 years ago
8 0

Before we begin please note that a jar is always cylindrical in shape if not mentioned otherwise. Thus, we will take a cylindrical jar in this case.

Since Kelly eats some of the salsa and the salsa in the jar is now 6 cm high, we know that Kelly ate the amount of Salsa whose volume is missing from the jar.

To find the missing volume on the Salsa jar all that we need to do is to find the height of the missing volume which is given to us as h= 6 cm. We already know that the radius of the jar, r=6 cm. Thus, the amount of Salsa Kelly has eaten is:

V=\pi(6)^2\times 6\approx678.6\approx679 cm^3

Thus, the third option is the correct answer

Juliette [100K]3 years ago
8 0
I'm positive that the answer is 565 cm^3
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a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

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Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

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Hence,

15.866% of 50,000 parts will fail to meet the specification

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Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

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P(x<48) = 0.9452

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Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

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