X=10 and X=3/4 basically it’s whatever X equals to make the inside the parentheses equal zero. So if I were to plug 10 into the first parentheses you’d have 10-10 which equals zero. Also the zero has to the the opposite sign of what’s in the parentheses. So if -10 is in the parentheses then the zero has to be the opposite so positive 10.

6 0

3 years ago

Please help me with 7 and 9 I’m really confused and I really need help!!

Margarita [4]

Answer:

7) K'(1, 1), N'(4, 0), Q'(4, 4)

9) F'(4, 2), W'(4, 5), K'(3, 2)

Step-by-step explanation:

When you are not sure about reflections and rotations, it can be useful to actually draw a graph. The line of reflection is the perpendicular bisector of the segment connecting a point with its image. That is, the image is the same distance from the line on the other side. A point that is on the line of reflection is "invariant," it doesn't move.

7) Reflecting across the x-axis changes the sign of the y-coordinate. That is all. Any point on the x-axis (y=0) is unchanged. The transformation is ...

(x, y) ⇒ (x, -y)

9) Reflecting across a vertical line changes the x-coordinate. The new value of x will be ...

x' = 6 - x

The "6" is double the x-coordinate of the vertical line. The transformation is ...

(x, y) ⇒ (6-x, y)

_____

Derivation of the formula for reflection on x=3

In general if M is the midpoint of a point (A) and its reflection (A'), then we have ...

M = (A +A')/2

2M = A + A'

2M -A = A'

When a point is reflected across a vertical line, all of the y-coordinate values remain unchanged. So, for A=(x, y) and M=(3, y), we have ...

A' = 2(3, y) -(x, y) = (6-x, 2y-y)

A' = (6 -x, y)

So, the reflection transformation across the line x = 3 is ...

(x, y) ⇒ (6-x, y)

6 0

3 years ago

Question 1

Vladimir79 [104]

We have that

question 1
Add or subtract.
4m2 − 10m3 − 3m2 + 20m3
=(4m2-3m2)+(20m3-10m3)
=m2+10m3

the answer is the option
B: m2 + 10m3

Question 2:
Subtract. (9a3 + 6a2 − a) − (a3 + 6a − 3)
=(9a3-a3)+(6a2)+(-a-6a)+(-3)
=8a3+6a2-7a-3

the answer is the option
B: 8a3 + 6a2 − 7a + 3

Question 3:
A company distributes its product by train and by truck. The cost of distributing by train can be modeled as −0.06x2 + 35x − 135, and the cost of distributing by truck can be modeled as −0.03x2 + 29x − 165, where x is the number of tons of product distributed. Write a polynomial that represents the difference between the cost of distributing by train and the cost of distributing by truck.

we have that
[the cost of distributing by train]-[the cost of distributing by truck]
=[−0.06x2 + 35x − 135]-[−0.03x2 + 29x − 165]
=(-0.06x2+0.03x2)+(35x-29x)+(-135+165)
=-0.03x2+6x+30

the answer is the option
C: −0.03x2 + 6x + 30

7 0

3 years ago