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3 years ago

A sample of carbon-12 has a mass of 6.00 g. How

Chemistry

1 answer:

dexar [7]3 years ago

8 0

Answer:

#atoms C-12 = 3.01 x 10²³

Explanation:

Convert grams to moles and multiply by Avogadro's Number.

6 g C-12 = (6g/12g·mol⁻¹) = 0.50 mol C-12

No. C-12 atoms in 0.50 mol C-12 = 0.50 mol C-12 x 6.02E23 atoms/mole = 3.01E23

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What describes an impermeable rock where oil and natural gas deposits are found ?

Alik [6]

Answer:

stone and gold is my impermeable

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3 years ago

Automobile airbags contain solid sodium azide, NaN 3 , that reacts to produce nitrogen gas when heated, thus inflating the bag.

Yuri [45]

<u>Answer:</u> The value of work for the system is -935.23 J

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium azide = 16.5 g

Molar mass of sodium azide = 65 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium azide}=\frac{16.5g}{65g/mol}=0.254mol$

The given chemical equation follows:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of sodium azide produces 3 moles of nitrogen gas

So, 0.254 moles of sodium azide will produce = $\frac{3}{2}\times 0.254=0.381mol$ of nitrogen gas

To calculate volume of the gas given, we use the equation given by ideal gas, which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = ?

T = Temperature of the gas = $22^oC=[22+273]K=295K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = 0.381 moles

Putting values in above equation, we get:

$1.00atm\times V=0.381mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 295K\\\\V=\frac{0.381\times 0.0821\times 295}{1.00}=9.23L$

To calculate the work done for expansion, we use the equation:

$W=-P\Delta V$

We are given:

P = pressure of the system = $1atm=1.01325\times 10^5Pa$ (Conversion factor: 1 atm = 101325 Pa)

$\Delta V$ = change in volume = $9.23L=9.23\times 10^{-3}m^3$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$W=-1.01325\times 10^5Pa\times 9.23\times 10^{-3}m^3\\\\W=-935.23J$

Hence, the value of work for the system is -935.23 J

7 0

4 years ago

GIVING BRAINLIEST FIVE STARS AND HEART!

iren [92.7K]

Explanation:

When an object is at rest, the body is said to possess potential energy. In another case, when the object is in motion, then it is said to possess kinetic energy. Potential energy tends to affect the object within the environment if and only when it gets transformed to other kinds of energy.

4 0

3 years ago

How does an increase in temperature affect the collisions of gas particles with the walls of the container?

Leno4ka [110]

Force of the collisions increases due to increase in temperature.

Explanation:

Increase in temperature affects the average speed and kinetic energy of the particles.

The average speed of the gas particles gets increased , Kinetic energy of the gas particles also gets increased.

If the volume is held constant, the increased speed of the gas molecules results in more frequent and more forceful collisions with the walls of the container, therefore increasing the pressure.

Therefore, force of the collisions increases due to increase in temperature.

7 0

4 years ago

A solution is made by dissolving 0.611 mol of NaCl in 250 g of water. If the molar mass of NaCl is 58.44 g/mol, what is the mola

shusha [124]

Molality= moles NaCl/ Kg H2O

250 g (1 Kg/ 1000 grams)= 0.250 Kg

Molality= 0.611 moles/ 0.250 Kg= 2.44 molal

6 0

3 years ago

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