1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goldenfox [79]
3 years ago
11

What is the relative formula mass of N2O? Ar of N = 14 and Ar of O = 16.

Chemistry
1 answer:
s2008m [1.1K]3 years ago
6 0

We have to calculate formula mass of N₂O.

The answer is: 44

Relative formula mass is the sum of relative atomic mass of constituent atoms in a formula unit of any compound.  Relative formula mass is represented as same symbol of relative molecular mass.

To calculate relative formula mass we need to know number of each atom in the formula and then adding atomic masses of all the atoms.

In N₂O, number of N-atom present is equal to 2 and number of O-atom is equal to  1.

Atomic mass of N-atom is 14 and atomic mass of O-atom is 16.

So, formula mass of N₂O is (2 X 14)+16 = 44.

You might be interested in
Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic
ale4655 [162]

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = 164.5\times 10^{-9} g

1 ng=10^{-9} g

Volume of the sample = V = 15.3 cm^3

Density of the lake water sample ,d= 1.00 g/cm^3

Mass of sample =  M = d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g

ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75

10.75 is the concentration of arsenic in the sample in parts per billion.

B)

Mass of arsenic in 1 cm^3  of lake water = \frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g

Mass of arsenic in 0.710 km^3 lake water be m.

1 km^3=10^{15} cm^3

Mass of arsenic in 0.710\times 10^{15} cm^3 lake water :

m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

\frac{2.74}{41.90} days

Then days required to remove 7,633.66 kg of arsenic from the lake water :

=7,633.66\times \frac{2.74}{41.90} days=499.19 days

1 year = 365 days

499.19 days = \frac{499.19}{365} years = 1.367 years\approx 1.37 years

C)

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

\frac{2.74}{41.90} days

Then days required to remove 7,633.66 kg of arsenic from the lake water :

=7,633.66\times \frac{2.74}{41.90} days=499.19 days

1 year = 365 days

499.19 days = \frac{499.19}{365} years = 1.367 years\approx 1.37 years

It will take 1.37 years to remove all of the arsenic from the lake.

6 0
3 years ago
Which form of co2 transport accounts for the greatest amount of co2 transported in blood?
ra1l [238]
The greatest amount of CO2 transported in blood is in the form of bicarbonate in plasma. Most of the carbon dioxide is converted into bicarbonate with the help of carbonic anhydrase which is an enzyme. This enzyme converts carborn dioxide and water into bicarbonate and hydrogen ions. The bicarbonate in plasma accounts for about 70% of CO2.
5 0
3 years ago
A buffer solution is made using a weak acid, HA. If the pH of the buffer is 9 and the ratio of A– to HA is 100, what is the pKa
sdas [7]
To calculate the pKa of the weak acid, we use the Henderson-Hasselbalch equation. It is expressed as pH = pKa - log [HA]/[A-]. This equation takes into account the concentration of the substance that does not dissociates into ions since it is a weak acid. We caculate as follows:

pH = pKa - log [HA]/[A-]
9 = pKa - log 1/100
pKa = 7
3 0
3 years ago
What is mandrake tuber
Rudiy27
It's botanical name would be Mandragora officianarum, and it has a humanoid shape. Its a murderous plant that grows from blood that grows in Mediterranean.
4 0
3 years ago
BaCl2(aq) + Na2CO3(aq) BaCO3(s) + NaCl(aq
Vitek1552 [10]
This is the equation balanced:

<span>BaCl2(aq) + Na2CO3(aq) = BaCO3(s) + 2 NaCl(aq)

Then the coefficient in front of Na Cl is 2.

Answer: 2
</span>


7 0
3 years ago
Other questions:
  • Carbon dioxide contains bonds between oxygen and carbon. What particles are between the carbon and oxygen atoms ? What keeps tho
    11·1 answer
  • If you have one kilogram of radionuclide, how much will remain after one half-life has passed?
    14·1 answer
  • A hypothesis is based on the analysis of data collected in a controlled
    8·2 answers
  • A researcher is using a small molecule as an inhibitor to manipulate a signaling pathway. This inhibitor prevents phosphorylatio
    9·1 answer
  • If you use 19 mL of 0.100 M KMnO4, how many moles have you used? The answer has to be in four decimal places (do not forget the
    14·1 answer
  • Which subatomic particle determines the identity of an atom
    15·1 answer
  • John and Lisa collected a sample of ocean water and placed it in a jar. Within a couple of days, the water had evaporated and sa
    11·1 answer
  • How did Wilma contribute to change in America
    9·1 answer
  • How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?
    12·1 answer
  • Draw every stereoisomer for 1,2‑difluoro‑1,2‑dimethylcyclopentane. Use wedge‑and‑dash bonds for the substituent groups, and be s
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!