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Llana [10]
2 years ago
9

What describes an impermeable rock where oil and natural gas deposits are found ?

Chemistry
1 answer:
Alik [6]2 years ago
3 0

Answer:

stone and gold is my impermeable

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Sha-vzwq-aby<br><br> Ladkiyoooooo aaa jaooo♡♥︎♡<br><br> Jaldiiiii karo na yaaaar
leva [86]

Answer:

kjajjahahayq :/

Explanation:

a sbywsbgv usnwbhx hg xw nx hb gs

5 0
2 years ago
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Write some example of misicible and immisicible liquid​
Eduardwww [97]

Explanation:

miscible liquids: water and alcohol

immiscible liquids: water and oil

4 0
3 years ago
I need help with this worksheet please
IrinaVladis [17]

starting with q.1 its the 2nd and 7th day

q.2 the 12th

q.3 is 8 days

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4 0
3 years ago
If 10.5 g copper chloride react with 12.4 g aluminum what is the limiting reactant
Brut [27]
Molar mass of copper chloride is 134.45 g/mole, so the mole of 10.5 g copper chloride is 10.5/134.45 = 0.078 mole.  Molar mass of aluminum is 27 g/mole, so the mole of 12.4 g aluminium is 12.4/27 = 0.46 mole.  The formula of this reaction is as follows, 2Al + 3CuCl2 ⇒ 2AlCl3 + 3Cu. Thus the molar ratio of the reactants is Al:CuCl2 = 2:3. So to react with 0.078 mole of copper chloride, will need 0.078 x 2/3 = 0.052 moles of aluminum which is less than the given amount (0.46mole).  Therefore, copper chloride is the limiting reactant.
8 0
3 years ago
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Using the balanced chemical reaction below, how many grams of copper (cu) metal can be obtained from 1.00 kg of copper ore (cu3f
aleksklad [387]

Answer : Mass of copper (Cu) metal obtained = 556.281 g

Solution : Given,

Mass of copper ore = 1 Kg = 1000 g

From the periodic table, the molar mass of copper and copper ore are

Molar mass of copper = 63.546 g/mole

Molar mass of copper ore, Cu_{3}FeS_{3} = 342.678 g/mole

First we have to calculate the number of moles of copper ore, Cu_{3}FeS_{3}

Moles of  Cu_{3}FeS_{3} = \frac{\text{ Mass of copper ore}}{\text{ Molar mass of copper ore}} = \frac{1000g}{342.678g/mole} = 2.918 moles

The balanced chemical reaction is :

2Cu_{3} FeS_{3}(s)+7O_{2}(g)\rightarrow 6Cu(s)+2FeO(s)+6SO_{2}(g)

From this chemical reaction, we conclude that

2 moles of Cu_{3}FeS_{3} gives          →     6 moles of Cu

2.918 moles of Cu_{3}FeS_{3} gives   →      \frac{6moles}{2moles}\times 2.918moles

                                                           = 8.754 moles

Thus, the Moles of copper (Cu) = 8.754 moles

Now, calculate the Mass of copper (Cu).

Mass of copper (Cu) = Moles of copper (Cu) × Molar mass of copper (Cu)

                                  = 8.757 moles × 63.546 g/moles

                                  = 556.281 g                                

4 0
3 years ago
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